Answer:
Step-by-step explanation:
An x value of 0 can only be plugged into the equation that has a domain that includes 0. The first function's domain is between -2 and -4, so 0 is not included in that domain. In the third function, the domain is between 1 and 3, so 0 is not included in that domain, either. The middle function's domain does include 0 (0 falls between -2 and 1) so we can only evaluate this function at an x value of 0.
g(0) = -0 - 1 so
g(0) = -1
Answer : <em>Equation of line is</em> y=Equation of line is y=
x+
Step-by-step explanation:
Theory :
Equation of line is given as y = mx + c.
Where, m is slope and c is y intercepted.
Slope of given line : y =
x+1 is m= 
We know that line : y =
x+1 is parallel to equation of target line.
therefore, slope of target line will be
.
we write equation of target line as y=
x+c
Now, It is given that target line passes through point ( -5,-2)
hence, point ( -5,-2) satisfy the target line's equation.
we get,
y=
x+c
-2=
-5+ c
-5=
+c
c= 
thus, Equation of line is y=Equation of line is y=
x+
4 is the greasy common factor
<h3>Volume of the cylinder:</h3>



<h3>Volume of the rectangular prism:</h3>



<h3>Total volume:</h3>

