Next time please indicate which problem you want to work on.
One example of an equation with variables present on both sides is
y-b = m(x-a). Given the slope of a line and one point (a,b) through which the line passes, you can come up with an equation of the line.
Or, given the numeric value of y-b and that of x-a, you could obtain the slope of the line thru the points (x,y) and (a,b).
3 3/4 divide 2 1/12 = 1.8
Assuming that a “circle graph” is a pie chart, the way of solving is this:
The degree of the angle of that pie section is relative to the entire circle just as the number of pyramids are to the number of total building blocks.
The number of pyramids out of the total is 30/150, or 1/5 (20%). This means that the angle of the section will be 1/5 the total angle measurement of the circle.
There are 360 degrees in a circle, and one fifth of this is 72 (360/5). Your answer is C.
A) The total number is the sum of all the frequencies
2+5+8+12+11+6=44
Answer: 44
B) The width is (upper limit - lower limit) / 2
(35-21) / 2 = 7
(50-36) / 2 = 7
(65-51) / 2 = 7
(80-66) / 2 = 7
(95-81) / 2 = 7
(110-96) / 2 = 7
Answer: the width is 7
C) The midpoint is the lower limit + the width
36+7=43
Answer: the midpoint is 43
D)The modal is the class with more frequency
In this case 66-80 with 12
Answer: class 66-80
E) We use the width formula
lower limit = 111
width = 7
upper = (width * 2) - lower
upper = (7 * 2) + 111
upper = 125
Answer: class 111-125
