3 3/4 divide 2 1/12<br><br><br> sssss

An article bought for rupees 350 is sold at a profit of 20% find its selling price

Mice21 [21]

Answer:

420

Step-by-step explanation:

20 percent of 350 is 70, so adding that on will give us the price it is sold at for profit of 70 (20%).

3 0

2 years ago

Read 2 more answers

Whats bigger 6/10 or 13/21

lidiya [134]

Answer: 13/21

Step-by-step explanation:

can i get brainiest pls

5 0

3 years ago

the radius of a circle is 5 meter what is the area,in square meter,of circle? Round to the nearest tenth

Slav-nsk [51]

Answer:

78.54 rounded to the tenths it is 78.5

Step-by-step explanation:

I did the math. And I did my work like this

5*5=25

25*pi=78.5398163

Rounded to hundredths 78.54

Rounded to tenths 78.5 Hope this helps, let me know if correct, and have a great day!!

6 0

2 years ago

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Consumer complaints are frequently reported to the Better Business Bureau. Industries with the most complaints to the Better Bus

Licemer1 [7]

Answer:

Let the complaints by Industry be CbI

CbI Frequency

Bank 26

Cable 44

Car 42

Cell 60

Collection 28

b) Percentages

CbI percentage (%)

Bank 13

Cable 22

Car 21

Cell 30

Collection 14

c) The industry with the highest number of complaints is the Cell Industry.

d) The Bar Chart is attached to this solution. It was constructed in the Ms Excel suite.

Step-by-step explanation:

a) The frequencies are simply the number of times each industry sector sent in a complaint. So, it's straight forward to present.

b) The percentage for each industry is done in comparison to the the total amount of complaints received.

Percentage for each industry = 100% × (Number of complaints from that industry)/(Total number of complaints)

Total amount of complaints received = 200

For Bank industry,

Percentage = 100% × (26/200) = 13%

For the Cable Industry,

Percentage = 100% × (44/200) = 22%

For Car industry,

Percentage = 100% × (42/200) = 21%

For Cell industry,

Percentage = 100% × (60/200) = 30%

For Collection industry,

Percentage = 100% × (28/200) = 14%

c) The industry with the highest number of complaints is the one with the highest frequency and percentage, and that is the Cell Industry.

d) The Bar Chart is attached to this solution. It was constructed in the Ms Excel suite.

7 0

2 years ago

Ship collisions in the Houston Ship Channel are rare. Suppose the number of collisions are Poisson distributed, with a mean of 1

alexandr1967 [171]

Answer:

$a) \simeq 0.3012$ $b) \simeq 0.0494$ c) $\simeq 0.2438$

Step-by-step explanation:

Rate of collision,

1.2 collisions every 4 months

or, $\frac{1.2}{4}$

= 0.3 collisions per month

So, the Poisson distribution for the random variable no. of collisions per month (X) is given by,

P(X =x) = $\frac{e^{-\lambda}\times {\lambda}^{x}}}{x!}
$

for x ∈ N ∪ {0}

= 0 otherwise --------------------------------------(1)

here, $\lambda = 0.3$ collision / month

No collision over a 4 month period means no collision per month or X =0

Putting X = 0 in (1) we get,

P(X = 0) = $\frac{e^{-0.3}\times {\0.3}^{0}}{0!}
$

$\simeq 0.7408182207$ ------------------------------------(2)

Now, since we are calculating this for 4 months,

so, P(No collision in 4 month period)

= $0.7408182207^{4}$

$\simeq 0.3012$ -----------------------------------------------------------(3)

2 collision in 2 month period means 1 collision per month or X =1

Putting X =1 in (1) we get,

P(X =1) = $\frac{e^{-0.3}\times {\0.3}^{1}}{1!}
$

$\simeq 0.2222454662$ ------------------------------------(4)

Now, since we are calculating this for 2 months, so ,

P(2 collisions in 2 month period)

= $0.2222454662^{2}$

$\simeq 0.0494$ -----------------------------------------(5)

1 collision in 6 months period means

$\frac{1}{6}$ collision per month

Now, P(1 collision in 6 months period)

= P( X = 1/6] (which is to be estimated)

= $\frac {P(X=0)\times 5 + P(X =1)\times 1}{6}$

= \frac {0.7408182207 \times 5 + 0.2222454662 \times 1}{6}[/tex]

$\simeq 0.6543894283$ -------------------------------------------(6)

So,

P(1 collision in 6 month period)

= $0.6543894283^{6}$

$\simeq 0.0785267444$ ------------------------------------------------(7)

So,

P(No collision in 6 months period)

= $(P(X =0)^{6}$

$\simeq 0.1652988882$ ---------------------------------(8)

so,

P(1 or fewer collision in 6 months period)

= (8) + (7 ) = 0.0785267444 +0.1652988882

$\simeq 0.2438$ ---------------------------------------------(9)

7 0

2 years ago

3 3/4 divide 2 1/12 sssss