Ask question

Ask question

All categories

3 years ago

11

I want a correct answer you can take your time. If I was born on December 24, two thousand and four ( 24 / 12 / 2004 ) and my cl

assmate was born on April 9, two thousand and six ( 09 / 04 / 2006 ), how many months, years and days are we apart?

1 answer:

Elden [556K]3 years ago

5 0

Answer:

8 months 11 days 1 year

You might be interested in

Help I need the answers in 20 minutes

Gelneren [198K]

2. 5 hours

3. $200

4. 9.5 hours. If it has to be whole numbers, 10 hours

Hope that helps!

<em>-scsb17hm</em>

6 0

3 years ago

Read 2 more answers

Two trains, Train A and Train B, simultaneously depart Station A and Station B. Station A and Station B are 252.5 miles apart fr

omeli [17]

-- The trains start moving at the same time.

-- The space between them is initially 252.5 miles.

-- They reduce the distance between them at the rate of (124.7+253.5)=378.2mph.

-- It will take them (252.5 / 378.2) = 0.6676 hour to meet.

That's 40min 3.49sec .

-- After tooting and puffing toward each other for 8 minutes, they still have <em>32min 3.49sec</em> to go before they meet each other. We're all hoping that they're on different tracks.

4 0

3 years ago

Write an equation in standard form of a line that passes through (4, 2) and is parallel to y = - 3/4 * x - 5 .

Bingel [31]

Answer:

y=2x+y-int

Step-by-step explanation:

If the line is parallet to the defined by the given equation the slope of the unknown line is m=2.

Use this value of slope to calculate the y intercept. 2 = ( 2 - y-int)/4 - 0)

THus, your equation is y = 2x + y-int

5 0

3 years ago

On your wedding day you leave for the church 34 minutes before the ceremony is to begin, which should be plenty of time since th

Schach [20]

Answer:

Average speed is 37.35 mi/h

Step-by-step explanation:

given data

leave = 34 minutes before

church distance = 12.0 miles

average speed first 17 minutes = 5.0 mi/h

solution

so we find Total distance travel in first 17 minutes = speed × time

Total distance travel in first 17 minutes = 5 × $\frac{17}{60}$

Total distance travel in first 17 minutes = 1.416 mi

and

Distance Remaining = 12 - 1.416 = 10.584 mi

Time Remaining = 34 - 17 min = 17 min

so

remaining distance Average speed = $\frac{distance}{time}$

Average speed = $\frac{10.584}{\frac{17}{60}}$

Average speed is 37.35 mi/h

3 0

3 years ago

Which pairs of matrices are inverses?

goblinko [34]

Answer:

B is the answer

Step-by-step explanation:

5 0

3 years ago