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3 years ago

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I want a correct answer you can take your time. If I was born on December 24, two thousand and four ( 24 / 12 / 2004 ) and my cl

assmate was born on April 9, two thousand and six ( 09 / 04 / 2006 ), how many months, years and days are we apart?

1 answer:

Elden [556K]3 years ago

5 0

Answer:

8 months 11 days 1 year

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3 intersecting lines are shown. A line contains points E, D, A, and B. Another line intersects the line at point A and contains

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Answer:

The one with arrows are the answers

->Line segment E B is bisected by Line segment D F .

->A is the midpoint of Line segment F C .

Line segment F C bisects Line segment D B.

->Line segment E B is a segment bisector.

->FA = One-halfFC.

Line segment D A is congruent to Line segment A B .

Step-by-step explanation:

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What is 4/6 ÷8/14???????????????

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A thermometer is taken from an inside room to the outside, where the air temperature is 20° f. after 1 minute the thermometer re

fomenos

The change in the temperature is proportional to the difference in temperatures. Let's call the initial temperature of the room and the thermometer $E_0$ and the current temperature $E(t)$ where $t$ is the elapsed time in minutes. The outside temperature is 20 F.

Newton's Law of Cooling:

$E(t) - 20 = (E_0 - 20) e^{- k t}$

We're given $E(1)=70 \textrm{ and } E(5)=45$

$70-20 = (E_0 - 20) e^{-k}$

$45-20 =(E_0 - 20) e^{-5k}$

Dividing,

$\dfrac{50}{25}=e^{4k}$

$k = \dfrac 1 4 \ln 2$

Now,

$E(t) - 20 = (E_0 - 20) e^{- k t}$

$E_0 = 20 + (E(t) - 20)e^{k t}$

$E_0 = 20 + (E(1) - 20)e^{k}$

$E_0 = 20 + (70 - 20)e^{\ln 2/4}$

$E_0 = 20 + 50 \cdot 2^{1/4} \approx 79.46 \textrm{ degrees F}$

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