Answer:

• We are gonna use the quotient rule

- u is (3√x + 2x)
- v is 4x²
- du/dx is 3/2√x
- dv/dx is 8x
• Therefore:

We have the expression:

When we have rational functions, where the denominator is a function of x, we have a restriction for the domain for any value of x that makes the denominator equal to 0.
That is because if the denominator is 0, then we have a function f(x) that is a division by zero and is undefined.
If we have a value that makes f(x) to be undefined, then this value of x does not belong to the domain of f(x).
Expression:

Answer: There is no restriction for x in the expression.
Answer:
The answer is 3,906.25
Step-by-step explanation:
All you have to do is divide 15,625 by 4! :)
Answer: n=p/2-m
Step-by-step explanation:
m=p/2-n (1)
Add n to both sides of the equation (1)
m+n=p/2-n+n => m+n=p/2 (2)
Subtract m from both sides of the equation (2)
m-m+n=p/2-m => n=p/2-m
X=-b/2a=4/14=2/7
Plug this value back into the function to find the corresponding Y value