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kirill115 [55]
3 years ago
6

Sorry last question :(

Mathematics
1 answer:
elena55 [62]3 years ago
6 0
Area of rectangle=30•12=360 square meters
Area of semicircle=3.14•15•15=353.25 square meters
360+353.25=713.25 square meters
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Name the intersection of planes DCG and EFG
cupoosta [38]
<span>GH would be the intersection in this case. This is the place where the planes come together. An intersection is where two things come together. This enables an object to create a shape like a box and gives support to the sides that mesh.</span>
7 0
3 years ago
What is the inverse answer for h(x)=x²+4?
lutik1710 [3]

Answer: 1.0/5. 7.

Step-by-step explanation:

5 0
3 years ago
An amusement park charges a $20 admission fee and $3 for each ride. Which equation can be used to determine c, the total cost of
PtichkaEL [24]

Answer:

C = 3n+20

Step-by-step explanation:

C= The Cost

n= the number of rides

So if you get on 2 rides

that would be $6

because 3x2=6

or 3+3

and just add in the 20 to get in

so the sum is

<em>2</em><em>6</em><em> </em><em>if</em><em> </em>you were to get on 2 rides

5 0
3 years ago
Find the exact value of tan(165°) using a difference of two angles
Katyanochek1 [597]

Answer:  -2+\sqrt{3}

=========================================================

Work Shown:

Apply the following trig identity

\tan(A - B) = \frac{\tan(A)-\tan(B)}{1+\tan(A)*\tan(B)}\\\\\tan(225 - 60) = \frac{\tan(225)-\tan(60)}{1+\tan(225)*\tan(60)}\\\\\tan(165) = \frac{1-\sqrt{3}}{1+1*\sqrt{3}}\\\\\tan(165) = \frac{1-\sqrt{3}}{1+\sqrt{3}}\\\\

Now let's rationalize the denominator

\tan(165) = \frac{1-\sqrt{3}}{1+\sqrt{3}}\\\\\tan(165) = \frac{(1-\sqrt{3})(1-\sqrt{3})}{(1+\sqrt{3})(1-\sqrt{3})}\\\\\tan(165) = \frac{(1-\sqrt{3})^2}{(1)^2-(\sqrt{3})^2}\\\\\tan(165) = \frac{(1)^2-2*1*\sqrt{3}+(\sqrt{3})^2}{(1)^2-(\sqrt{3})^2}\\\\\tan(165) = \frac{1-2\sqrt{3}+3}{1-3}\\\\\tan(165) = \frac{4-2\sqrt{3}}{-2}\\\\\tan(165) = -2+\sqrt{3}\\\\

----------------------

As confirmation, you can use the idea that if x = y, then x-y = 0. We'll have x = tan(165) and y = -2+sqrt(3). When computing x-y, your calculator should get fairly close to 0, if not get 0 itself.

Or you can note how

\tan(165) \approx -0.267949\\\\-2+\sqrt{3} \approx -0.267949

which helps us see that they are the same thing.

Further confirmation comes from WolframAlpha (see attached image). They decided to write the answer as \sqrt{3}-2 but it's the same as above.

5 0
3 years ago
Determine whether y varies directly with x. y-2x=0
skelet666 [1.2K]
<span>hi,  </span>
<span>you can determine it by seeing if y/x = a constant value, in other words if y = (a constant value) x </span>
<span>then you say that y varies directly with x, and you can see that : call the constant k </span>
<span>then y/x is supposed to be k in all values </span>
<span>6/3 = 2 </span>
<span>24/12 =2  </span>
<span>96/48 = 2 </span>
<span>384/192 = 2 </span>
<span>it worked the ratio between x and y is constant so y varies directly with x ( y = 2x) and that constant k =2 </span>
<span>p.s. you can also say that x varies directly with y but in that case it becomes x/y =constant and that constant say c is 1/2 (x = (1/2)y)) </span>
<span>hope u understand.

Source- </span>https://answers.yahoo.com/question/index?qid=20110813112602AApHZtQ
4 0
3 years ago
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