Answer:
A = 222 units^2
Step-by-step explanation:
To find the area of this trapezoid, first draw an imaginary horizontal line parallel to AD and connecting C with AB (Call this point E). Below this line we have the triangle CEB with hypotenuse 13 units and vertical side (21 - 16) units, or 5 units. Then the width of the entire figure shown can be obtainied using the Pythagorean Theorem:
(5 units)^2 + CE^2 = (13 units)^2, or 25 + CE^2 = 169. Solving this for CE, we get |CE| = 12.
The area of this trapezoid is
A = (average vertical length)(width), which here is:
(21 + 16) units
A = --------------------- * (12 units), which simplifies to:
2
A = (37/2 units)(12 units) = A = 37*6 units = A = 222 units^2
Answer:
.
Step-by-step explanation:
Notice that the first two factors are in the form 
, which is equal to 
. Start by combining and expanding these two factors:
Let 
.
.
.
This expression can now be expressed as 
. 
stands the unit imaginary number, where 
. Unless is raised to a certain power other than 
, it can be treated just like a constant.
Expand this expression using FOIL:
.
Answer:
1. x + 24 = 3x
24 = 3x - x
24 = 2x
12 = x
3x
3 (12)
36
2. 10x - 27 = 7x
10x - 7x = 27
3x = 27
x = 9
7x
7 (9)
63
3. 5x + 1 = 6x - 13
5x - 6x = -13 - 1
-x = -14
x = 14
5x + 1
5 (14) + 1
71
4. 6x + 3 = 4x + 39
6x - 4x = 39 - 3
2x = 36
x = 18
6x + 3
6 (18) + 3
111
1. B
2. A
3. H
4. E
