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Sedbober [7]
3 years ago
11

Help Me Please!

Mathematics
1 answer:
djverab [1.8K]3 years ago
3 0
First step is to order the data from least to greatest.
10.5 11 11.5. 14.5 14.5 17 17 18 19
The median (Q2) is the middle number 14.5, this separates the lower half from the upper half. Q1 is the middle of the lower half, since there are an even amount of data, you have to take the average of the two middle numbers, 11 & 11.5, that would be 11.25; now we have to do the same with the upper half to find Q3, the average between 17 & 18 is 17.5
Now to find the IQR, subtract Q3 - Q1,
17.5 - 11.25 = 6.25
IQR = 6.25
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Solve for x: -6 <x-1 <9​
WINSTONCH [101]

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3 0
3 years ago
Pwease help fast this is mah last question!
inessss [21]

Answer:

A  = 222 units^2

Step-by-step explanation:

To find the area of this trapezoid, first draw an imaginary horizontal line parallel to AD and connecting C with AB  (Call this point E).  Below this line we have the triangle CEB with hypotenuse 13 units and vertical side (21 - 16) units, or 5 units.  Then the width of the entire figure shown can be obtainied using the Pythagorean Theorem:

(5 units)^2 + CE^2 = (13 units)^2, or 25 + CE^2 = 169. Solving this for CE, we get |CE| = 12.

The area of this trapezoid is

A = (average vertical length)(width), which here is:

       (21 + 16) units

A  = --------------------- * (12 units),   which simplifies to:

                  2

A = (37/2 units)(12 units)  =  A  = 37*6 units  =  A  = 222 units^2

8 0
3 years ago
PLEASE HELP and explain! ill give brainliest if you do
EastWind [94]

Area of the rectangle

= l  \times b

= 8 \times 6

= 48 {in}^{2}

Area of the semicircles

= 2 \times ( \frac{1}{2} \pi {r}^{2} )

= \pi {r}^{2}

= \pi {3}^{2}

= 9\pi

= 9 \times 3.14

= 28.26 {in}^{2}

Area of the figure

= 48 + 28.26

= 76.26 {in}^{2}

= 76.3in²

(rounded)

6 0
2 years ago
Read 2 more answers
Multiply? I don't know how to do this o.o<br><br> (X+4√2) (x-4√2) (x-3i)
Korolek [52]

Answer:

x^{3} -(3i) \; x^{2} -32x + 96 i.

Step-by-step explanation:

Notice that the first two factors are in the form (x-a)(x+a), which is equal to (x^{2} - a^{2}). Start by combining and expanding these two factors:

Let a = 4\sqrt{2}.

a^{2} = 16 \times 2 = 32.

(x + a) (x - a) = x^{2} - a^{2} = x^{2} -32.

This expression can now be expressed as (x^{2} - 32)(x - 3i). i stands the unit imaginary number, where i^{2} = -1. Unless i is raised to a certain power other than 1, it can be treated just like a constant.

Expand this expression using FOIL:

\begin{aligned}&(x^{2} - 32)(x - 3i)\\=&\underbrace{x^{2}\cdot x}_{\verb!F!} +\underbrace{(x^{2})(-3i)}_{\verb!O!} + \underbrace{(-32)x}_{\verb!I!} + \underbrace{(-32)(-3i)}_{\verb!L!}\\=& x^{3} -(3i)x^{2}-32x + 96i \end{aligned}.

6 0
3 years ago
If you don’t know the real answer don’t give me a fake one I just need help!
PtichkaEL [24]
Answer:
1. x + 24 = 3x
24 = 3x - x
24 = 2x
12 = x

3x
3 (12)
36

2. 10x - 27 = 7x
10x - 7x = 27
3x = 27
x = 9

7x
7 (9)
63

3. 5x + 1 = 6x - 13
5x - 6x = -13 - 1
-x = -14
x = 14

5x + 1
5 (14) + 1
71

4. 6x + 3 = 4x + 39
6x - 4x = 39 - 3
2x = 36
x = 18

6x + 3
6 (18) + 3
111

1. B
2. A
3. H
4. E

8 0
3 years ago
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