Answer:
V=12.6148888506L
Explanation:
using charles law Volume1/Temperature1 = Volume2/Temperature2
13.4L/(17C+273.15C)=V/273.15K
remember gas equations require kelvin not celcius so converting celcius to kelvin is Celcius + 273.15 which is standard temperature conditions
a nucleic acid
Explanation: The nucleic acids, both DNA and RNA, consist of polymers ofnucleotides. The nucleotides are linked covalently between the 3' carbon atom of the pentose and thephosphate group attached to the 5' carbon of the adjacent pentose
Answer is: mass of oxygen is 12,576 grams.
Missing chemical reaction: 2KClO₃ → 2KCl + 3O₂.
m(KCl) = 19,6 g.
n(KCl) = m(KCl) ÷ M(KCl).
n(KCl) = 19,6 g ÷ 74,55 g/mol.
n(KCl) = 0,262 mol.
From chemical reaction: n(KCl) : n(O₂) = 2 : 3.
n(O₂) = 3 · 0,262 mol ÷ 2.
n(O₂) = 0,393 mol.
m(O₂) = n(O₂) · M(O₂).
m(O₂) = 0,393 mol · 32 g/mol.
m(O₂) = 12,576 g.
20.06 g of Hg and 1.6 g of O₂
<u>Explanation:</u>
To Find:
Number of Mercury and oxygen that can be obtained from 21.7 g of HgO
First we have to write the balanced equation for the decomposition reaction of Mercury(II) oxide as,
2 HgO (s) → 2Hg(l) + O₂ (g)
21.7 g of HgO = 
= 0.1 mol of HgO.
As per the above equation, we can find the mole ratio between HgO and Hg is 1: 1 and that of HgO and oxygen is 2:1 .
So amount of Hg produced = 0.1 mol × 200.59 g / mol ( molar mass of Hg)
= 20.06 g of Hg
Amount of oxygen produced = 0.05 mol × 32 g/ mol = 1.6 g of O₂
Thus it is clear that 20.06 g of Hg and 1.6 g of O₂ is obtained from 21.7 g of HgO
Weak acids only partially ionize. so the retain part of the original molecule. C
