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iVinArrow [24]
3 years ago
5

suppose that recording station N located 200 km north of the epicenter of an earthquake, and recording station S is located 100

on south of the epicenter of the same earthquake. Which of the following statements would be true
Chemistry
1 answer:
andrezito [222]3 years ago
6 0

Answer:

c.The value of T at Recording Station N would be greater than T at Recording Station S.

Explanation:

We can deduce from the information provided that the value of T at recording station N would be greater than T at recording station S.

This problem relates distance with time.

       Speed  = \frac{disance}{time}

                  Distance  = Speed x time

  • Just like any other physical quantity, speed of a substance is directly related to time.
  • The larger the time taken the farther the distance it will cover assuming the velocity is constant.
  • Earthquake waves for example moves at constant speed with a unique velocity in earth materials.
  • The farther the distance, the more time it will take to reach the seismic recording station.
  • Since N is a distance of 200km from the epicenter, it will take a greater time and have a higher reading of T to reach the station.
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63.9 grams. Yes, the Nacl was converted.  Maximum possible ppm is 540ppm.

Explanation:

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7 0
3 years ago
how many kilograms of water must evaporate from 8kg of a 25% salt solution to produce 40% salt solution?
Lena [83]

Answer: The kilograms of water must evaporate from 8kg of a 25% salt solution to produce 40% salt solution is 3 kg.

Explanation:

According to the ratio and proportion:

C_1m_1=C_2m_2

where,

C_1 = concentration of ist solution = 25%

m_1 = mass of ist solution = 8 kg

C_2 = concentration of second solution = 40%

m_2 = mass of second solution = ? kg

25\times 8=40\times m_2

m_2=5kg

Thus the final solution must have a mass of 5 kg , i.e (8-5)= 3 kg of mass must be evaporated.

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6 0
3 years ago
!: (a) 20 cm: 80
RoseWind [281]

Answer:

THE LENGTH OF THE AIR COLUMN IS 9.5 CM

Explanation:

Taking the atmospheric pressure to be 760 mmHg;

When the capillary tube is held horizontally, the pressure of the tube is 760 mmHg

when the capillary tube is held vertically, the pressure increases by 4 cm = 40 mm

The new pressure of the tube is hence, 760 + 40 mmHg = 800 mmHg

Using the pressure forlmula;

P1 V1 = P2 V2

P1 A1 L1 = P2 A2 L2

where A1 and A2 is the area of the capillary tube and it is equal, it cancels out.

P1 l1 = P2 l2

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The length of the air in the tube is 9.5 cm.

5 0
3 years ago
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6 0
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