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puteri [66]
2 years ago
15

How do I do a balancing equation. I understand. Can you show me a step by step on how to do one of the equations that aren't don

e?

Chemistry
1 answer:
sasho [114]2 years ago
8 0
To balance a chemical equation, you first must count the number of each of the atoms on both the left hand side - reactant side and the right hand side - product side of the chemical reaction.

After counting the atoms, make a tally of the atoms on both sides, for instance if it is hydrogen - h, record the number of hydrogen atoms on the reactant and product side. Then, place coefficients at appropriate places for the elements and or compounds, to basically have all of the different kinds of atoms from their respective elements equal the same on both the left and right side of the reaction.

SnO2 + H2 > Sn + H2O
1st count the metals - Sn atoms on both sides -
Sn left side - 1
Sn right side - 1

2nd count the oxygen atoms on both sides
O atom left side - 2
O atom right side - 1.

Here, the atoms are not the same, so place a coefficient on the side with the least number of oxygen atoms, right side, put 2 to balance.

Now O atoms are same on both sides, 2 atoms but, there are 4 hydrogen atoms now,

Since 2H2O = 2H2 + 2O = H = 4 and O = 2.

Now place the coefficient of 2 on the side with Hydrogen atoms by itself, left side, now this also gives us 4 hydrogens.

So balanced equation:
SnO2 + 2H2 > Sn + 2H2O.
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Answer:

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Explanation:

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3 0
2 years ago
What are the branches of chemistry and their definition?
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Which two or more substances combine but keeps it properties​
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3 years ago
A student sees an absorbance a=1.140 for his solution that has a concentration of c=1.50*10-4 m using 0.50 cm cuvette. what is t
777dan777 [17]

The molar extinction coefficient is 15,200 M^{-1} cm^{-1}.

The formula to be used to calculate molar extinction coefficient is -

A = ξcl, where A represents absorption, ξ refers molar extinction coefficient, c refers to concentration and l represents length.

The given values are in required units, hence, there is no need to convert them. Directly keeping the values in formula to find the value of molar extinction coefficient.

Rewriting the formula as per molar extinction coefficient -

ξ = \frac{A}{cl}

ξ = \frac{1.140}{1.5*10^{-4}*0.5 }

Performing multiplication in denominator to find the value of molar extinction coefficient

ξ = \frac{1.140}{0.000075}  

Performing division to find the value of molar extinction coefficient

ξ = 15,200 M^{-1} cm^{-1}

Hence, the molar extinction coefficient is  15,200 M^{-1} cm^{-1}.

Learn more about molar extinction coefficient -

brainly.com/question/14744039

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The reaction for the combustion of methane is shown below. If 28.70g of methane
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