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puteri [66]
3 years ago
15

How do I do a balancing equation. I understand. Can you show me a step by step on how to do one of the equations that aren't don

e?

Chemistry
1 answer:
sasho [114]3 years ago
8 0
To balance a chemical equation, you first must count the number of each of the atoms on both the left hand side - reactant side and the right hand side - product side of the chemical reaction.

After counting the atoms, make a tally of the atoms on both sides, for instance if it is hydrogen - h, record the number of hydrogen atoms on the reactant and product side. Then, place coefficients at appropriate places for the elements and or compounds, to basically have all of the different kinds of atoms from their respective elements equal the same on both the left and right side of the reaction.

SnO2 + H2 > Sn + H2O
1st count the metals - Sn atoms on both sides -
Sn left side - 1
Sn right side - 1

2nd count the oxygen atoms on both sides
O atom left side - 2
O atom right side - 1.

Here, the atoms are not the same, so place a coefficient on the side with the least number of oxygen atoms, right side, put 2 to balance.

Now O atoms are same on both sides, 2 atoms but, there are 4 hydrogen atoms now,

Since 2H2O = 2H2 + 2O = H = 4 and O = 2.

Now place the coefficient of 2 on the side with Hydrogen atoms by itself, left side, now this also gives us 4 hydrogens.

So balanced equation:
SnO2 + 2H2 > Sn + 2H2O.
You might be interested in
The dissolution of calcium chloride in water is given by the following equation:
never [62]

Answer:

The reactants would appear at a higher energy state than the products.

Have a nice day!

8 0
2 years ago
What mass, in grams, of CO2 and H2O<br> is formed from 2.55 mol of propane?
oksian1 [2.3K]

Answer:

336.6 grams of CO₂ and 183.6 grams of H₂O are formed from 2.55 moles of propane.

Explanation:

In this case, the balanced reaction is:

C₃H₈ + 5 O₂ → 3 CO₂ + 4 H₂O

By stoichiometry of the reaction (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of reactant and product participate in the reaction:

  • C₃H₈: 1 mole
  • O₂: 5 moles
  • CO₂: 3 moles
  • H₂O: 4 moles

Being the molar mass of each compound:

  • C₃H₈: 44 g/mole
  • O₂: 16 g/mole
  • CO₂: 44 g/mole
  • H₂O: 18 g/mole

Then, by stoichiometry, the following quantities of mass participate in the reaction:

  • C₃H₈: 1 mole* 44 g/mole= 44 grams
  • O₂: 5 moles* 16 g/mole= 80 grams
  • CO₂: 3 moles* 44 g/mole= 132 grams
  • H₂O: 4 moles* 18 g/mole= 72 grams

So you can apply the following rules of three:

  • If by stoichiometry 1 mole of C₃H₈ forms 132 grams of CO₂, 2.55 moles of C₃H₈ how much mass of CO₂ will it form?

mass of CO_{2} =\frac{2.55 moles of C_{3} H_{8}*132 gramsof CO_{2} }{ 1 mole of C_{3} H_{8}}

mass of CO₂= 336.6 grams

  • If by stoichiometry 1 mole of C₃H₈ forms 72 grams of H₂O, 2.55 moles of C₃H₈ how much mass of H₂O will it form?

mass of H_{2}O =\frac{2.55 moles of C_{3} H_{8}*72 gramsof H_{2}O }{ 1 mole of C_{3} H_{8}}

mass of H₂O= 183.6 grams

<u><em>336.6 grams of CO₂ and 183.6 grams of H₂O are formed from 2.55 moles of propane.</em></u>

3 0
3 years ago
Nagine you are repeatedly lifting a weight into the air up to a height of 2 m. Assuming in each litt
Mariulka [41]

Answer:

A

Explanation:

8 0
3 years ago
A 1.000 gram sample of an alcohol was burned in oxygen to produce 1.913 g of CO2 and 1.174 g of H20. The alcohol contained only
ycow [4]
The formula of alcohol are
1.913 g CO2/44 = 0.043 moles of CO2*12 = 0.043 moles of C 1.174 gram H2O/18 = 0.065 moles of H.
O: 1 - 0.516 g C - 13 g H = 0.354 g O/16 = 0.022 moles of O.
we have 0.043:0.130.;0.022 as C:H:O. Diving by the smallest no. 0.022 we get 1.95:5.9:1 or 2:6:1 as C:H:O.

hope this help 
4 0
3 years ago
Read 2 more answers
What is the total volume of solution that was dispensed from this burette?
kykrilka [37]

Answer:

it will a i did the quiz got it all right

Explanation:

5 0
3 years ago
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