1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Lesechka [4]
3 years ago
6

1 2/3 × 2 1/3= in fraction form

Mathematics
2 answers:
Ray Of Light [21]3 years ago
7 0
First convert them into improper fractions.

\sf 1\dfrac{2}{3}\times 2\dfrac{1}{3}

To convert into an improper fraction, keep the denominator the same, multiply the denominator to the whole number and add it to the numerator.

\sf 3\times 1+2=5
\sf 3\times 2+1=7

So we have:

\sf\dfrac{5}{3}\times\dfrac{7}{3}

Now multiply the numerators and denominators together:

\sf\dfrac{35}{9}

Revert back to mixed number form. Nine goes into thirty-five three times.

9 * 3 = 27
35 - 27 = 8

So we will have 3 and 8/9 left over or \boxed{\sf 3\dfrac{8}{9}}
REY [17]3 years ago
6 0
The answer is 3 8/9 because you turn it into a mixed number which is 5/3*7/3. Once you multiply you get 35/9. Since it is an improper fraction you turn it into a mixed number by dividing 35/9. In the end, you get 3 8/9 as your final answer. 
You might be interested in
What is the answer to 7/5 = 10.5/b
Pavlova-9 [17]

Answer: b=14.7

Step-by-step explanation:

6 0
3 years ago
True or false. Y=3xsquared (like the little number two above the x) is direct variation.
galina1969 [7]
Your answer will be true
3 0
3 years ago
Please help me with this.
-Dominant- [34]

Answer:

3

Step-by-step explanation:

Parenthesis

Exponents

Multiplication

Division

Addition

Subtraction

3^4 +9^2÷3^3-9^2

81+81÷27-81

81+3-81

3

5 0
3 years ago
Write a real world problem that could be solved by using the equation <img src="https://tex.z-dn.net/?f=3x-25%3D125" id="TexForm
forsale [732]

Answer:

x=50

See below for word problem.

Step-by-step explanation:

While shopping, you spend $125 before tax. You buy 3 dresses at the same price each and receive a $25 discount. How much is the price of each dress?

3x-25=125

3x=125+25

3x=150

x=50

8 0
3 years ago
[tex]\frac{12}{20} =_____% = _____ hundredths
Over [174]

The percentage form of given fraction is 60% and the hundredths form is 0.60

According to the statement

we have given that the a fraction and we have to find the percentage of that fraction and write in the form hundredths.

So, For this purpose,

The given fraction is 12/20.

Then the definition of the percentage is that

The Percentage, a relative value indicating hundredth parts of any quantity.

so, the percentage of given fraction is :

Percentage fraction = 12/20 * 100

After solving it, The percentage fraction will become:

Percentage fraction = 60%

and Now convert into the hundredths form then

In the hundredths form it will become

from 60% to 0.60.

So, The percentage form of given fraction is 60% and the hundredths form is 0.60

Learn more about Percentage here

brainly.com/question/843074

#SPJ1

8 0
2 years ago
Other questions:
  • In the diagram, what is mAngleVSR?
    6·2 answers
  • The totally clean toothpaste company advertises that 9/10 of all people surveyed prefer their toothpaste what percent of people
    15·1 answer
  • Help solving this problem for algebra
    8·1 answer
  • Alison's car travels at 65 miles per hour. How far does she travel in 4.5 hours?
    5·1 answer
  • Select each angle that has a measure of 30
    5·2 answers
  • What is the difference between 128.04 and 8.287?
    6·1 answer
  • How would I find the equation of the line of best fit for this table<br> x 7 9 11<br> y 12.4 13 16
    11·1 answer
  • PLS ANSWER ASAP FOR BRAINLYEST!!!!!!!!!!! DUE TODAY!!!!!
    5·1 answer
  • Solve for the missing side length. If necessary round to the nearest tenth.
    6·1 answer
  • Can someone please compare and contrast 4 of the logarithmic functions and their inverse exponential functions ?
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!