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timurjin [86]
3 years ago
7

Taylor ran 57 minutes on Tuesday and 48 minutes on Saturday. Mark ran 62 minutes on Tuesday and 53 minutes on Saturday. Taylor s

aid they ran the same total time and mark said they didn’t. Who is right? Explain using comparative relational thinking.
Mathematics
2 answers:
marusya05 [52]3 years ago
8 0

Let's compare!

Taylor ran 57 + 48 mins total. Sum would be 105 mins.

Mark ran 62 + 53 mins total. Sum would be 115 mins.

Clearly, the two sums are different when we compare them using subtraction.

115 - 105 = 10. Mark ran 10 mins longer than Taylor.

vovikov84 [41]3 years ago
6 0

No they didn’t. So that makes mark right, because I’m an hour there is 60mins so Taylor’s time—57+48=105-60=45 that would be 1.45 (1hr45mins) Marks time— 62+53=115-60=55 so that would be 1.55(1hr55mins)

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Write 165% as a decimal and as a mixed number or fraction in spimplest form
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Answer:

1.65

Step-by-step explanation:

because every percentage is 100

therefore 165/100 = 1.65

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Answer:

Step-by-step explanation:

(29, 35) (43, 21)

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36?

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2 years ago
What is the value of X?<br> A 57 B 48 C 38 D 28
olga_2 [115]

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Step-by-step explanation:

The 3 interior angles of a triangle always add up to 180

Soooo:

95 + 57 = 152

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5 0
3 years ago
The probability that a randomly selected box of a certain type of cereal has a particular prize is 0.20.
MatroZZZ [7]

Answer:

a) the probability is 0.0734 (7.34%)

b) the probability is 0.7382 (73.82%)

c) 10 boxes

Step-by-step explanation:

Since each box is independent of the others and defining the random variable X= number of boxes of cereal purchased without prices until having 2 prices , then X has a negative binomial distribution . Thus

P(X=k)= C(k+r-1,k)*p^k *(1-p)^r

where

p= probability to not obtain a price when a box is purchased = 1- 0.2 = 0.8

C ( ) = combinations

k = number of boxes without prices

r= number of boxes with prices=2

P(X=k) = probability of purchasing k boxes without prices until obtaining r boxes with prices

a) for k= 8 - r = 6

P(X=6)= C(7,6)*0.8^6*0.2^2 = 7*0.8^6*0.2^2 = 0.0734 (7.34%)

b) for k≥9-2=7

P(X≥7) = 1- P(X<7)= 1- Fn(X=7)

where Fn(X) is the cumulative negative binomial distribution. We can calculate it through its relationship with the cumulative binomial distribution Fb(X) that is easily found in tables :

Fn(k=7,r=2,p=0.8) = Fb(k=7,n=k+r=9,p=0.8) = 0.2618

thus

P(X≥7) = 1- P(X<7)= 1- Fn(X=7) = 1-  0.2618 = 0.7382 (73.82%)

c) the expected value E(X) for a negative binomial distribution is

E(X)= p*r/(1-p) = 0.8*2/0.2 = 8 boxes that do not contain prices

thus

n=k+r = 8 + 2 = 10 boxes

6 0
3 years ago
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