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astra-53 [7]
3 years ago
5

Which lines have slope -4/5 and contain point (0,1)?

Mathematics
1 answer:
Oksanka [162]3 years ago
6 0
I believe it was BC, to find that answer, you simply find the point (0,1) where 0 is x and y is 1. There were two lines which made me not think twice but since it is negative, the lines should be going to the left side rather than the right. So the slope which is y over x of -4/5, to find that, you count up 4 and over 5
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The probability of an outcome that lies within 68% of the mean is a good indicator that it lies in which standard deviation?
kotegsom [21]
Yes the probability of an outcome that lies within 68% is a good indicator that lies in which standard deviation.

8 0
3 years ago
Help me please, kinda lost
Dmitry_Shevchenko [17]

Answer:

400cm^2

Step-by-step explanation:

For this question, you need to find the surface areas of both objects, then add them together.

For the cube:

56cm for the front

56cm for the back

42cm for the side

42cm for the other side

48cm for the top

48cm for the bottom

SA for the cube: 292cm^2

For the triangle, things are a little different. We do the same process that we did to find the SA of the cube, but we do not have to find the SA of the top side (because there isn't a top side) and we have to divide the total SA by 2 because it's a triangle.

For the triangle:

42cm for the front

42cm for the back

54cm for the slanted side

42cm for the other side

36cm for the bottom

SA for the triangle: (216/2)^2=108cm^2

292+108=400cm^2

the SA of the composite figure is 400cm^2

8 0
3 years ago
What is (f-g)(x)?<br><br> f(x)=x^4-x^2+9<br> g(x)=x^3+3x^2+12
sweet-ann [11.9K]
X^4 - x^2 + 9 - (x^3 + 3x^2 + 12) =

x^4 - x^3 - 4x^2 - 3
6 0
3 years ago
I'LL GIVE BRAINLIST JUST PLZ HELP ME
Evgen [1.6K]

Answer:

12 * 24 * 17 = 4896

10 * 12 * 4 = 480

4896 + 480 = 5376

the volume is 5376 cubic inches.

7 0
3 years ago
Read 2 more answers
3. (05.06 MC)
AveGali [126]

Answer:

Step-by-step explanation:

y > 3x + 10

y < -3x - 1

<h3> Part A:</h3>

You'd graph the given systems of linear inequalities the same way as you graph the linear equations.  

To graph y > 3x + 10, plot the y-intercept, (0, 10), then use the slope, m = 3 (rise 3, run 1), to plot other points on the graph.  Use a dashed line (because of the ">" symbol).  

Follow the same steps for the other linear inequality. Plot the y-intercept, (0, -1), then use the slope, m = -3 (down 3, run 1) to plot other points. Use a dashed line (because of the "<" symbol).  

Pick a test point on either side of the boundary line and plug it into the original problem.  This will help determine which side of the boundary line is the solution.  Plug in a test point that is not on the boundary line.

Use the point of origin, (0, 0) as the test point. Plug in these values into the given systems of linear inequalities to see whether it will provide a true statement.  

y > 3x + 10

0 > 3(0) + 10

0 > 0 + 10

0 > 10 (False statement).  

y < -3x - 1

0 < -3(0) - 1

0 < 0 - 1

0 < -1 (false statement).  

Since the point of origin provided a false statement to the given systems of linear inequalities, you must shade the half-plane region where it doesn't contain the test point.  

<h3>Part B: </h3>

You'll do the same process as what I've done for the test point. Plug in the values of (8, 10) into the given systems of linear inequalities. If it provides a false statement, then it means that it is not a solution to the system.  

y > 3x + 10

10 > 3(8) + 10

10 > 24 + 10

10 > 34 (False statement).  

y < -3x - 1  

10 < -3(8) - 1

10 < -24 - 1

10 < -25 (false statement).  

Therefore, (8, 10) is not a solution to the system.    

8 0
3 years ago
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