9514 1404 393
Answer:
a) E = 6500 -50d
b) 5000 kWh
c) the excess will last only 130 days, not enough for 5 months
Step-by-step explanation:
<u>Given</u>:
starting excess (E): 6500 kWh
usage: 50 kWh/day (d)
<u>Find</u>:
a) E(d)
b) E(30)
c) E(150)
<u>Solution</u>:
a) The exces is linearly decreasing with the number of days, so we have ...
E(d) = 6500 -50d
__
b) After 30 days, the excess remaining is ...
E(30) = 6500 -50(30) = 5000 . . . . kWh after 30 days
__
c) After 150 days, the excess remaining would be ...
E(150) = 6500 -50(150) = 6500 -7500 = -1000 . . . . 150 days is beyond the capacity of the system
The supply is not enough to last for 5 months.
The right answer for the question that is being asked and shown above is that: "fraction with numerator negative 3 minus i and denominator 10." This is the simplified expression fraction with numerator of the square root of negative one and denominator of the quantity three plus eight times i minus the <span>quantity two plus five times i.</span>
Answer:
4 x (7-x)
Step-by-step explanation:
4 times (multiply) the difference (subtraction) of 7 and a number (seeing as how you don't know that number use a variable, x)
y = -2/3x - 4
simply plug into y = mx+b where m is slope and b is y intercept
This is the commutative property (of addition, but this applies to multiplication as well)
It doesn't matter which order the numbers are added in, the same result will be achieved.
1+2 = 2+1
2*4 = 4*2
