The answers should be: (-2,5), (-2,-2), (-6,-1), (2,1)
Hope this helped :)
Answer:
![(a)\dfrac{92}{117}](https://tex.z-dn.net/?f=%28a%29%5Cdfrac%7B92%7D%7B117%7D)
![(b)\dfrac{8}{39}](https://tex.z-dn.net/?f=%28b%29%5Cdfrac%7B8%7D%7B39%7D)
![(c)\dfrac{25}{117}](https://tex.z-dn.net/?f=%28c%29%5Cdfrac%7B25%7D%7B117%7D)
Step-by-step explanation:
Number of Men, n(M)=24
Number of Women, n(W)=3
Total Sample, n(S)=24+3=27
Since you cannot appoint the same person twice, the probabilities are <u>without replacement.</u>
(a)Probability that both appointees are men.
![P(MM)=\dfrac{24}{27}X \dfrac{23}{26}=\dfrac{552}{702}\\=\dfrac{92}{117}](https://tex.z-dn.net/?f=P%28MM%29%3D%5Cdfrac%7B24%7D%7B27%7DX%20%5Cdfrac%7B23%7D%7B26%7D%3D%5Cdfrac%7B552%7D%7B702%7D%5C%5C%3D%5Cdfrac%7B92%7D%7B117%7D)
(b)Probability that one man and one woman are appointed.
To find the probability that one man and one woman are appointed, this could happen in two ways.
- A man is appointed first and a woman is appointed next.
- A woman is appointed first and a man is appointed next.
P(One man and one woman are appointed)![=P(MW)+P(WM)](https://tex.z-dn.net/?f=%3DP%28MW%29%2BP%28WM%29)
![=(\dfrac{24}{27}X \dfrac{3}{26})+(\dfrac{3}{27}X \dfrac{24}{26})\\=\dfrac{72}{702}+\dfrac{72}{702}\\=\dfrac{144}{702}\\=\dfrac{8}{39}](https://tex.z-dn.net/?f=%3D%28%5Cdfrac%7B24%7D%7B27%7DX%20%5Cdfrac%7B3%7D%7B26%7D%29%2B%28%5Cdfrac%7B3%7D%7B27%7DX%20%5Cdfrac%7B24%7D%7B26%7D%29%5C%5C%3D%5Cdfrac%7B72%7D%7B702%7D%2B%5Cdfrac%7B72%7D%7B702%7D%5C%5C%3D%5Cdfrac%7B144%7D%7B702%7D%5C%5C%3D%5Cdfrac%7B8%7D%7B39%7D)
(c)Probability that at least one woman is appointed.
The probability that at least one woman is appointed can occur in three ways.
- A man is appointed first and a woman is appointed next.
- A woman is appointed first and a man is appointed next.
- Two women are appointed
P(at least one woman is appointed)![=P(MW)+P(WM)+P(WW)](https://tex.z-dn.net/?f=%3DP%28MW%29%2BP%28WM%29%2BP%28WW%29)
![P(WW)=\dfrac{3}{27}X \dfrac{2}{26}=\dfrac{6}{702}](https://tex.z-dn.net/?f=P%28WW%29%3D%5Cdfrac%7B3%7D%7B27%7DX%20%5Cdfrac%7B2%7D%7B26%7D%3D%5Cdfrac%7B6%7D%7B702%7D)
In Part B, ![P(MW)+P(WM)=\frac{8}{39}](https://tex.z-dn.net/?f=P%28MW%29%2BP%28WM%29%3D%5Cfrac%7B8%7D%7B39%7D)
Therefore:
![P(MW)+P(WM)+P(WW)=\dfrac{8}{39}+\dfrac{6}{702}\\$P(at least one woman is appointed)=\dfrac{25}{117}](https://tex.z-dn.net/?f=P%28MW%29%2BP%28WM%29%2BP%28WW%29%3D%5Cdfrac%7B8%7D%7B39%7D%2B%5Cdfrac%7B6%7D%7B702%7D%5C%5C%24P%28at%20least%20one%20woman%20is%20appointed%29%3D%5Cdfrac%7B25%7D%7B117%7D)
I'm pretty sure quadrant II (2,2)
Answer:
132.233 ft2
Step-by-step explanation:
Let's call the width of the rectangle 'w' and the length 'x'. So the area of the semicircle is:
![A_1 = \pi*radius^2/2](https://tex.z-dn.net/?f=A_1%20%3D%20%5Cpi%2Aradius%5E2%2F2)
![A_1 = \pi*(w/2)^2/2](https://tex.z-dn.net/?f=A_1%20%3D%20%5Cpi%2A%28w%2F2%29%5E2%2F2)
![A_1 = \pi/8*w^2](https://tex.z-dn.net/?f=A_1%20%3D%20%5Cpi%2F8%2Aw%5E2)
And the area of the rectangle is:
![A_2 = w*x](https://tex.z-dn.net/?f=A_2%20%3D%20w%2Ax)
If the perimeter of the window is 41 feet, we have:
![Perimeter = length + 2*width + \pi*radius](https://tex.z-dn.net/?f=Perimeter%20%3D%20length%20%2B%202%2Awidth%20%2B%20%5Cpi%2Aradius)
![41 = x + 2*w + \pi*w/2](https://tex.z-dn.net/?f=41%20%3D%20x%20%2B%202%2Aw%20%2B%20%5Cpi%2Aw%2F2)
![x = 41 - w(2 + \pi/2)](https://tex.z-dn.net/?f=x%20%3D%2041%20-%20w%282%20%2B%20%5Cpi%2F2%29)
Now, the equation for the total area of the window is:
![A = A_1 + A_2 = \pi/8*w^2 + w*x](https://tex.z-dn.net/?f=A%20%3D%20A_1%20%2B%20A_2%20%3D%20%5Cpi%2F8%2Aw%5E2%20%2B%20w%2Ax)
![A = \pi/8*w^2 + w*(41 - w(2 + \pi/2))](https://tex.z-dn.net/?f=A%20%3D%20%5Cpi%2F8%2Aw%5E2%20%2B%20w%2A%2841%20-%20w%282%20%2B%20%5Cpi%2F2%29%29)
![A = (\pi/8-2 - \pi/2)*w^2 + 41w = -3.1781w^2 + 41w](https://tex.z-dn.net/?f=A%20%3D%20%28%5Cpi%2F8-2%20-%20%5Cpi%2F2%29%2Aw%5E2%20%2B%2041w%20%3D%20-3.1781w%5E2%20%2B%2041w)
To find the maximum area, we can find the x-coordinate of the vertex of the quadratic equation:
![x\_vertex = -b / 2a = -41 / (-3.1781*2) = 6.45](https://tex.z-dn.net/?f=x%5C_vertex%20%3D%20-b%20%2F%202a%20%3D%20-41%20%2F%20%28-3.1781%2A2%29%20%3D%206.45)
So the width that gives us the maximum area of the window is 6.45 feet, and the area will be:
![A = -3.1781w^2 + 41w = -3.1781*(6.45)^2 + 41*6.45 = 132.233\ ft^2](https://tex.z-dn.net/?f=A%20%3D%20-3.1781w%5E2%20%2B%2041w%20%3D%20-3.1781%2A%286.45%29%5E2%20%2B%2041%2A6.45%20%3D%20132.233%5C%20ft%5E2)