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3 years ago

Describe a system of linear equations that has no solution.

3 answers:

8 0

The two lines in this system have the same slope, but different values for b. This means the lines are parallel. The lines don't intersect, so there are no solutions and the system is inconsistent. Because the lines are not the same the equations are independent.

Galina-37 [17]3 years ago

5 0

X = 10
x = 4
_____
by substitution 10 = 4 which is patently false, thus the system has no solutions. Admittedly this is an over simplified example

Paris lover 822 years ago

0 0

Sample Response/Explanation: A system consisting of lines that do not intersect will have no solution. Lines will not intersect if they have the same slope, but different y-intercepts. Parallel lines have the same slope, which means they will never intersect.

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3 years ago

PLEASE ANSWER THIS ITS URGENT

Oksi-84 [34.3K]

Answer:

Option C

Explanation:

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2 years ago

Read 2 more answers

Parallelogram TUVW is graphed on a coordinate plane with vertices at T (3, 4), V (-10,-2), V(-6,5),

zalisa [80]

The coordinates of the dilated vertex V' is (-6p, 5p)

Transformation is the movement of a point from its initial location to a new location. Types of transformation are translation, reflection, rotation and dilation.

Dilation is the increase or decrease in the size of a figure. If a point A(x, y) is dilated by a factor k, the new point is A'(kx, ky).

The Parallelogram TUVW has vertices at T(3, 4), U(-10,-2), V(-6,5) and W (7,11). If it is dilated by a scale factor p with the origin, the new point is at:

T'(3p, 4p), U'(-10p, -2p), V'(-6p, 5p) and W'(7p, 11p)

Find out more on dilation at:brainly.com/question/10253650

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3 years ago

A square has an area of 4 square centimeters. What is the length of one side, in centimeters?

Lunna [17]

Answer:

2 cm

Step-by-step explanation:

$\sqrt{4 cm^{2}} =2 cm$

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3 years ago

A statistics textbook chapter contains 60 exercises, 6 of which are essay questions. A student is assigned 10 problems. (a) What

Scilla [17]

Answer:

a) P=0.3174

b) P=0.4232

c) P=0.2594

d) The shape of the hypergeometric, in this case, is like a binomial with mean np=1.

Step-by-step explanation:

The appropiate distribution to model this is the hypergeometric distribution:

$P(X=x)=\frac{\binom{s}{x}\binom{N-s}{M-x}}{\binom{N}{M}}=\frac{\binom{6}{x}\binom{54}{10-x}}{\binom{60}{10}}$

a) What is the probability that none of the questions are essay?

$P(X=0)=\frac{\binom{6}{0}\binom{54}{10-0}}{\binom{60}{10}}\\\\P(X=0)=\frac{1*(54!/(10!*44!)}{60!/(10!*50!)} =\frac{2.3931*10^{10}}{7.5394*10^{10}} = 0.3174$

b) What is the probability that at least one is essay?

$P(X=1)=\frac{\binom{6}{1}\binom{54}{9}}{\binom{60}{10}}\\\\P(X=1)=\frac{6*(54!/(9!*43!)}{60!/(10!*50!)} =\frac{3.1908*10^{10}}{7.5394*10^{10}} =0.4232$

c) What is the probability that two or more are essay?

$P(X\geq2)=1-(P(0)+P(1))=1-(0.3174+0.4232)=1-0.7406=0.2594$

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4 years ago