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3 years ago

What is the answer to this too?

Mathematics

2 answers:

Yuri [45]3 years ago

7 0

Answer:

Step-by-step explanation:

This one sounds the most confident, being a call to action. It is good to end a thought with motion.

den301095 [7]3 years ago

6 0

C is answer for this question

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10(8r+23) =1430 <br> HELP PLS ITS FOR MY HW PLS PLS PLS

Mademuasel [1]

Answer:

r = 15

Step-by-step explanation:

10(8r + 23) = 1430

Divide both sides by 10.

8r + 23 = 143

Subtract 23 from both sides.

8r = 120

Divide both sides by 8.

r = 15

7 0

3 years ago

the perimeter of an isosceles trapezoid is 62 cm. if three sides are equal in length and the fourth side is 10 cm longer, find t

Alja [10]

Perimeter = sum of all the sides
let x = one side
longer side = x + 10
Perimeter = x + x + x + x + 10
62 = 4x + 10
4x = 52
x = 13
Longer side = 23

Area = (10+23)x2/10
= 6.6

5 0

3 years ago

Read 2 more answers

What are the initial value and rate of change from this table???? Explain!!

Evgen [1.6K]

Answer:

rent goes up 9 dollars at a time while number of days is 1 at a time

Step-by-step explanation:

the difference of 21 and 12 is 9 so you can see it changes every day by nine for the ratio i think is for every day 9 dollars is added to fee

8 0

3 years ago

a gym teacher has a large canvas bag that contains 8 tennis balls, 2 volleyballs, 1 basketball, 3 baseballs, and 5 footballs. if

Serga [27]

Answer:

Step-by-step explanation:

5+1+3+8+2=19

3/19 = 16%

6 0

2 years ago

Drag the tiles to the correct boxes to complete the pairs not all tiles will be used match each quadratic graph to its respectiv

ch4aika [34]

Answer:

Part 1) The function of the First graph is $f(x)=(x-3)(x+1)$

Part 2) The function of the Second graph is $f(x)=-2(x-1)(x+3)$

Part 3) The function of the Third graph is $f(x)=0.5(x-6)(x+2)$

See the attached figure

Step-by-step explanation:

we know that

The quadratic equation in factored form is equal to

$f(x)=a(x-c)(x-d)$

where

a is the leading coefficient

c and d are the roots or zeros of the function

Part 1) First graph

we know that

The solutions or zeros of the first graph are

x=-1 and x=3

The parabola open up, so the leading coefficient a is positive

The function is equal to

$f(x)=a(x-3)(x+1)$

Find the value of the coefficient a

The vertex is equal to the point (1,-4)

substitute and solve for a

$-4=a(1-3)(1+1)$

$-4=a(-2)(2)$

$a=1$

therefore

The function is equal to

$f(x)=(x-3)(x+1)$

Part 2) Second graph

we know that

The solutions or zeros of the first graph are

x=-3 and x=1

The parabola open down, so the leading coefficient a is negative

The function is equal to

$f(x)=a(x-1)(x+3)$

Find the value of the coefficient a

The vertex is equal to the point (-1,8)

substitute and solve for a

$8=a(-1-1)(-1+3)$

$8=a(-2)(2)$

$a=-2$

therefore

The function is equal to

$f(x)=-2(x-1)(x+3)$

Part 3) Third graph

we know that

The solutions or zeros of the first graph are

x=-2 and x=6

The parabola open up, so the leading coefficient a is positive

The function is equal to

$f(x)=a(x-6)(x+2)$

Find the value of the coefficient a

The vertex is equal to the point (2,-8)

substitute and solve for a

$-8=a(2-6)(2+2)$

$-8=a(-4)(4)$

$a=0.5$

therefore

The function is equal to

$f(x)=0.5(x-6)(x+2)$

3 0

3 years ago