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natita [175]
4 years ago
13

Cyclohexene, a hydrocarbon, has a molar mass of 82.1 g/mole. if the combustion of 0.8300 g cyclohexene produces 0.9102 g h2o and

2.668 g co2, what is the molecular formula of this compound?
Chemistry
2 answers:
adelina 88 [10]4 years ago
8 0

Answer is:  the molecular formula is C₆H₁₀.

Chemical reaction: C₆Hₓ + yO₂ → 6CO₂ + x/2H₂O.

m(H₂O) = 0.9102; mass of the water.

n(H₂O) = m(H₂O) ÷ m(H₂O)  

n(H₂O) = 0,9102 g ÷ 18 g/mol

n(H₂O) = 0,0505 mol.

From chemical reaction: n(H) = 2 · n(H₂O).

n(H) = 0.101 mol.

m(CO₂) = 2.668 g; mass of carbon dioxide.

n(CO₂) = 2.668 g ÷ 44 g/mol.

n(CO₂) = 0.0606 mol; amount of the substance.

n(CO₂) = n(C) = 0.0606 mol.

n(C) : n(H) = 0.606 mol : 0.101 mol.

n(C) : n(H) = 6 : 10; proportion of carbon and hydrogen atoms in cyclohexene.

melisa1 [442]4 years ago
7 0

<em>Answer:</em>

  • The molecular formula will be C6H10.

<em>Explanation;</em>

<em>Given Data:</em>

  • mass of compound =   0.8300 g
  • mass of H2O          =   0.9102 g
  • mass of CO2          =   2.668 g

Solution:

% of C = (mass of CO2/mass of compound)× (12/44)×100

% of C = (2.66÷0.8300)×(12/44)× 100 = 87.40 %

% of H = (mass of H2O/mass of compound)× (2/18)×100

% of H =  (0.910÷0.8300)× (2/18)×100 = 12.18 %

Niiw we calculate moles of C and H from % as follow

moles of C = 87.40/12 = 7.2 mol

moles of H = 12.18/1 = 12.18 mol

In we take atomic ratio

                 C     :     H

         12.18/7.2 :   7.2/7.2

           1.69       :     1

multiply atomic ratio by 3 to get whole no.

  C : H = 3 (1.69:1) = 5 : 3

So empirical formula is C3H5.

<em>Calculations of molecular formula:</em>

empirical formula mass of C3H5 = 41

  n = molar mass of compound /empirical formula mass

 n = 82.1/41   = 2

Molecular mass =  n × empirical formula = 2 × C3H5 = C6H10

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kramer

Answer:

the proton and the neutron

Explanation:

mass of The proton is approximately  1.6726 × 10^-27 Kg

mass of the electron  is approximately 9.109 × 10^-31 Kg

mass of the neutron  is approximately 1.6749 × 10^-27 Kg

Here we see that mass of proton and neutron is approximately similar.

_____________________________________________

Lets see what is  the mass of these particle IN atm unit

mass of these particles can also be described in form of amu(atomic mass unit)

1 atm is the mass defined as 1/12 th of mass of the carbon-12(c-12) atom.

In terms of unit atm

mass of proton = 1 amu

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hence we can say that mass of proton = mass of neutron.

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This makes option four the neutron and the atom , the wrong choice.

correct answer is the proton and the neutron

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5 0
3 years ago
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7nadin3 [17]

What is pollen in the reproduction cycle of flowering plants?

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4 0
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zavuch27 [327]

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