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tamaranim1 [39]
2 years ago
8

Entir What is the striking back of the bunsen- burner?

Chemistry
1 answer:
svp [43]2 years ago
6 0

Answer:

With too little air, the gas mixture will not burn completely and will form tiny carbon particles that are heated to glowing, making the flame luminous. With too much air, the flame may burn inside the burner tube; that is, it may strike back.

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What is the compound of c4?
klio [65]

Answer:

c4 is an explosive..

contains RDX, DOS, DOA, and PIB.

Explanation:

5 0
3 years ago
How many moles of ethanol C2H6O, are in a 10.0g sample​
Brrunno [24]

Answer: 0.217 mol

Explanation:

To find the amount of moles in a 10 g sample, we need the molar mass of ethanol.

Molar Mass: 46.07 g/mol

Now that we have the molar mass, we can find moles.

10.0 g*\frac{1mol}{46.07g}=0.217 mol

We know that there are 0.217 mol in a 10.0 gram sample.

6 0
3 years ago
If the sea floor is spreading,why is the Earth not getting bigger?
TEA [102]
Because the the sand on the sea for is very compact and the water salt and chemicals make it compact making it stick together and fill up holes or cracks before going anyhere
4 0
3 years ago
Read 2 more answers
A student increases the temperature of a 417cm³ balloon from 278k to 231k. Assuming constant pressure, what should the new volum
viva [34]
Charles law states that volume of gas is directly proportional to temperature at constant pressure 
V/T = k
where V - volume , T - temperature and k - constant
\frac{V1}{T1} =  \frac{V2}{T2}
where parameters for the first instance are on the left side and parameters for the second instance are on the right side of the equation 

in the question it states that the temperature has been increased from 278 K to 231 K but it should actually be temperature is decreased from 278 K to 308 K
substituting the values in the equation 
\frac{417cm^{3} }{278K} =  \frac{V}{308 K}
V = 462 cm³
the answer should be D. 462 cm³ 
3 0
3 years ago
3. Burns from boiling water can be severe, caused by the transfer of energy from the boiling water to the
Free_Kalibri [48]

Answer:

Q = 3937.56  J

Explanation:

Heat transferred due to change in temperature is given by :

Q=mc\Delta T

c is the specific heat of water, c=4.18 J/g-°C

We have, m = 15 g, T_i=100^{\circ} C\ \text{and}\ T_f=37.2^{\circ} C

So,

Q=15\times 4.18\times (37.2-100)\\Q=-3937.56\ J

Hence, 3937.56  J of heat is transferred.

8 0
3 years ago
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