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tamaranim1 [39]
2 years ago
8

Entir What is the striking back of the bunsen- burner?

Chemistry
1 answer:
svp [43]2 years ago
6 0

Answer:

With too little air, the gas mixture will not burn completely and will form tiny carbon particles that are heated to glowing, making the flame luminous. With too much air, the flame may burn inside the burner tube; that is, it may strike back.

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The Average Speed of the orbiting space shuttle is
maxonik [38]

Explanation:

It is given that, the Average Speed of the orbiting space shuttle is  17500 miles/hour.

We need to convert the speed in kilometers/ second

We know that,

1 mile = 1.609 km

or

1 km = 0.621 miles

1 hour = 3600 seconds

17500\ \dfrac{\text{miles}}{\text{hour}}=17500\ \dfrac{\text{miles}}{\text{h}}\times \dfrac{1\ h}{3600\ s}\\\\=17500\times \dfrac{\text{miles}}{3600\ s}

Now cancel the miles in numerator.

17500\times \dfrac{\text{miles}}{3600\ s}=17500\times \dfrac{\text{miles}}{3600\ s}\times \dfrac{1.609\ km}{1\ \text{miles}}\\\\=17500\times \dfrac{1.609}{3600}\ km/s\\\\=7.82\ km/s

So, 17500 miles/hour is equal to 7.82 km/s.

8 0
3 years ago
The great French chemist Antoine Lavoisier discovered the Law of Conservation of Mass in part by doing a famous experiment in 17
yawa3891 [41]

Answer:

a. 2 HgO(s) ⇒ 2 Hg(l) + O₂(g)

b. 0.957 g

Explanation:

Step 1: Write the balanced equation

2 HgO(s) ⇒ 2 Hg(l) + O₂(g)

Step 2: Convert 130.0 °C to Kelvin

We will use the following expression.

K = °C + 273.15

K = 130.0°C + 273.15

K = 403.2 K

Step 3: Calculate the moles of O₂

We will use the ideal gas equation.

P × V = n × R × T

n = P × V/R × T

n = 1 atm × 0.0730 L/0.0821 atm.L/mol.K × 403.2 K

n = 2.21 × 10⁻³ mol

Step 4: Calculate the moles of HgO that produced 2.21 × 10⁻³ moles of O₂

The molar ratio of HgO to O₂ is 2:1. The moles of HgO required are 2/1 × 2.21 × 10⁻³ mol = 4.42 × 10⁻³ mol.

Step 5: Calculate the mass corresponding to 4.42 × 10⁻³ moles of HgO

The molar mass of HgO is 216.59 g/mol.

4.42 × 10⁻³ mol × 216.59 g/mol = 0.957 g

5 0
3 years ago
Highlight the claim.
Dahasolnce [82]

Answer:

The claim is: Therefore Mitosis requires less energy than sexual reproduction does.

Explanation:

8 0
3 years ago
The reaction described in Part A required 3.40 L of sodium chloride. What is the concentration of this sodium chloride solution
Mumz [18]

Answer:

Part A:

First, convert molarity to moles by multiplying by the volume:

0.293 M AgNO3 = (0.293 moles AgNO3)/1 L x 1.19 L = 0.349 moles AgNO3

5 0
3 years ago
What are the 4 forms of precipitation
yKpoI14uk [10]
If Im not wrong i think its rain,snow,hail,and sleet...hope this helps you

5 0
3 years ago
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