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MrRa [10]
3 years ago
7

The molarity of a solution prepared by dissolving 4.11 g of NaI in enough water to prepare 312 mL of solution is

Chemistry
1 answer:
Dimas [21]3 years ago
6 0

Answer:

The correct answer is 8.79 × 10⁻² M.

Explanation:

Based on the given information, the mass of NaI given is 4.11 grams. The molecular mass of NaI is 149.89 gram per mole. The moles of NaI can be determined by using the formula,

No. of moles of NaI = Weight of NaI/ Molecular mass

= 4.11 / 149.89

= 0.027420

The vol. of the solution given is 312 ml or 0.312 L

The molarity can be determined by using the formula,

Molarity = No. of moles/ Volume of the solution in L

= 0.027420/0.312

= 0.0879 M or 8.79 × 10⁻² M

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a. dkg

1 kg is equivalent to 100 decagram (dkg)

therefore 0.00684 kg is = 100 dkg/kg x 0.00684 kg = 0.684 dkg

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b. 1 kg is equivalent to 1000 g

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