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4 years ago

PbSO4 → PbSO3 + O2 Balance the equation

Chemistry

1 answer:

erastova [34]4 years ago

5 0

Answer:

2PbSO4 → 2PbSO3 + O2

Explanation:

in original equation we notice that we have one extra oxygen, which we cannot form a O2 with, so by multiplying everything else by 2, we get 2 extra oxygen

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Iron and vanadium both have the BCC crystal structure and V forms a substitutional solid solution in Fe for concentrations up to

Bess [88]

Answer:

Explanation:

To find the concentration; let's first compute the average density and the average atomic weight.

For the average density $\rho_{avg}$ ; we have:

$\rho_{avg} = \dfrac{100}{ \dfrac{C_{Fe} }{\rho_{Fe}} + \dfrac{C_v}{\rho_v} }$

The average atomic weight is:

$A_{avg} = \dfrac{100}{ \dfrac{C_{Fe} }{A_{Fe}} + \dfrac{C_v}{A_v} }$

So; in terms of vanadium, the Concentration of iron is:

$C_{Fe} = 100 - C_v$

From a unit cell volume $V_c$

$V_c = \dfrac{n A_{avc}}{\rho_{avc} N_A}$

where;

$N_A$ = number of Avogadro constant.

SO; replacing $V_c$ with $a^3$ ; $\rho_{avg}$ with $\dfrac{100}{ \dfrac{C_{Fe} }{\rho_{Fe}} + \dfrac{C_v}{\rho_v} }$ ; $A_{avg}$ with $\dfrac{100}{ \dfrac{C_{Fe} }{A_{Fe}} + \dfrac{C_v}{A_v} }$ and

$C_{Fe}$ with $100-C_v$

Then:

$a^3 = \dfrac { n \Big (\dfrac{100}{[(100-C_v)/A_{Fe} ] + [C_v/A_v]} \Big) } {N_A\Big (\dfrac{100}{[(100-C_v)/\rho_{Fe} ] + [C_v/\rho_v]} \Big) }$

$a^3 = \dfrac { n \Big (\dfrac{100 \times A_{Fe} \times A_v}{[(100-C_v)A_{v} ] + [C_v/A_Fe]} \Big) } {N_A \Big (\dfrac{100 \times \rho_{Fe} \times \rho_v }{[(100-C_v)/\rho_{v} ] + [C_v \rho_{Fe}]} \Big) }$

$a^3 = \dfrac { n \Big (\dfrac{100 \times A_{Fe} \times A_v}{[(100A_{v}-C_vA_{v}) ] + [C_vA_Fe]} \Big) } {N_A \Big (\dfrac{100 \times \rho_{Fe} \times \rho_v }{[(100\rho_{v} - C_v \rho_{v}) ] + [C_v \rho_{Fe}]} \Big) }$

Replacing the values; we have:

$(0.289 \times 10^{-7} \ cm)^3 = \dfrac{2 \ atoms/unit \ cell}{6.023 \times 10^{23}} \dfrac{ \dfrac{100 (50.94 \g/mol) (55.84(g/mol)} { 100(50.94 \ g/mol) - C_v(50.94 \ g/mol) + C_v (55.84 \ g/mol) } }{ \dfrac{100 (7.84 \ g/cm^3) (6.0 \ g/cm^3 } { 100(6.0 \ g/cm^3) - C_v(6.0 \ g/cm^3) + C_v (7.84 \ g/cm^3) } }$

$2.41 \times 10^{-23} = \dfrac{2}{6.023 \times 10^{23} } \dfrac{ \dfrac{100 *50*55.84}{100*50.94 -50.94 C_v +55.84 C_v} }{\dfrac{100 * 7.84 *6}{600-6C_v +7.84 C_v} }$

$2.41 \times 10^{-23} (\dfrac{4704}{600+1.84 C_v})=3.2 \times 10^{-24} ( \dfrac{284448.96}{5094 +4.9 C_v})$

$\mathbf{C_v = 9.1 \ wt\%}$

4 0

3 years ago

Explain how carbon is conserved in the carbon cycle.

jek_recluse [69]

<h2> Interconversion of energy.</h2>

Explanation:

Carbon moves from plants and animals to soils in the form of cycle.
When we take in oxygen we release carbon dioxide gas $(CO_{2})$ into the atmosphere.
Animals and plants give carbon dioxide gas through the process called respiration and transpiration.
From fossil fuels carbon moves in the atmosphere.
The fuels like wood or coal when burned releases carbon dioxide into the atmosphere.
The Matter is conserved in the carbon cycle as carbon absorbs energy and then it releases the same amount of energy.
Carbon changes from one form to another, but the total amount of carbon remains the same.

8 0

3 years ago

Calculate the number of moles of Cl atoms in 3.01×1024 formula units of magnesium chloride, MgCl2.

natta225 [31]

Answer: 10 moles
To find how many moles, you need to divide the number of atoms with 6.02 * 10^23. Since every magnesium chloride has two chlorine atoms, you need to multiply it by 2. The calculation would be: 3.01×10^24 * 2 / 6.02 * 10^23= 10 moles

8 0

3 years ago

Read 2 more answers

How many moles of solute particles are present in 1 mL (exact) of aqueous 0.0040 M Ba(OH)2?

lidiya [134]

The number of mole of solute particles are present in 1 mL (exact) of aqueous 0.0040 M Ba(OH)₂ is 0.000004 mole

<h3>What is molarity? </h3>

Molarity is defined as the mole of solute per unit litre of solution. Mathematically, it can be expressed as:

Molarity = mole / Volume

With the above formula, we can determine the number of mole present in the solution. Detail below:

<h3>How to determine the mole of the solute in the solution</h3>

Volume of solution = 1 mL = 1 / 1000 = 0.001 L
Molarity of solution = 0.004 M
Mole of solute =?

Molarity = mole / Volume

Cross multiply

Mole = Molarity × volume

Mole of solute = 0.004 × 0.001

Mole of solute = 0.000004 mole

Thus, the mole of the solute in the solution is 0.000004 mole

Learn more about molarity:

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6 0

2 years ago

Which of the following items may NOT be recycled?

LenKa [72]

paper towels cannot be recycled because the fibers are too short to be made into new paper.

Gloves may not be recycled.

Broken glass may not be recycled because they can contaminate the glass recycling process.

ANSWER: none of the above

8 0

3 years ago