I think it's easiest to find the pOH from the given [OH-] first.
-log(1x10^-5)
pOH=5
Then find the pH.
pOH+pH=14
5+pH=14
pH=9
Then find the [H+] using the pH.
antilog(-9) (if you dont have an antilog button use 10^-9)
[H+]=1x10^-9
<u>Answer:</u> The correct answer is Option c.
<u>Explanation:</u>
Vaporization is defined as the physical process in which liquid particles get converted to gaseous particles.
The value of standard Gibbs free energy is 0 for equilibrium reactions.
To calculate 
for the reaction, we use the equation:
where,
= standard entropy change of vaporization
= standard enthalpy change of vaporization = 30.7 kJ/mol = 30700 J/mol (Conversion factor: 1 kJ = 1000 J)
T = temperature of the reaction = 353.3 K
Putting values in above equation, we get:
Hence, the correct answer is Option c.
The first diagram is showing carboxylic acid because carboxyl contains a Carbon atom as the central atom bonded with OH group, a double bonded Oxygen, hydrogen ofc, and a lone R group.
2. It is ester group
3. Correct its ether
4. It's the exact diagram for ethyl alcohol, so correct
WOOT WOOOT
Answer:
It is not "strong acids have a low pH"
Explanation:
I feel it should because that is a true statement but for Primavera it is wrong.
