Answer:
D. 7
Step-by-step explanation:
Divide the number into odd-numbered and even-numbered digits (starting counting digit number 1 from the right).
odd digits: d, 0, 5, 6, 3, 1, 8, 3 . . . . sum of 26+d
even digits: 8, 1, 3, 2, 0, 3, 2, 4 . . . sum of 23
<em>Multiply the sum of even-numbered digits by 2, and add 1 for each even-numbered digit* that is 5 or greater: 23×2 +1 = 47</em>
<em>Add this to the sum of odd-numbered digits, and choose "d" so the result is a multiple of 10.</em>
47 + (26+d) = 73+d
The next higher multiple of 10 is 80. For the total to be 80, d = 7.
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* The actual algorithm is described as "for each product of a digit and 2 that is greater than 9, subtract 9 from the product." Doing that, the number added to the sum will be ...
- for 5: 2×5 - 9 = 1
- for 6: 2×6 - 9 = 3
- for 7: 2×7 - 9 = 5
- for 8: 2×8 - 9 = 7
- for 9: 2×9 - 9 = 9
In each case, the number contributed to the sum is 1 more than twice the digit, mod 10.