Step 1:
first let us convert the two decimals into fractions.
0.36=36/100 (since there are two digits after decimal point we divide by 100)
2.4=24/10 (since there are one digit after decimal point we divide by 10)
now we can multiply the fractions
×
multiplying numerator with numerator and denominator with denominator:

=
Now we can convert this back to decimal
864/1000=0.864, moving decimal three digits to the left since we have three zeros in the denominator that is 1000.
Answer=0.864
Answer:
Area of shaded region=41 square feet
Area of non shaded region= 87 square feet
Step-by-step explanation:
As, Shaded area is made of different shapes including two rectangles and one triangle
So,
Area of shaded region,

Area of non shaded region=total area of rectangular region-Shaded region

Answer:
Step-by-step explanation:
STEPS FOR SOLVING LINEAR EQUATION
3y=4x+1
Swap sides so that all variable terms are on the left hand side.
4x+1=3y
Subtract 1 from both sides.
4x=3y−1
Divide both sides by 4.
4
4x
=
4
3y−1
Dividing by 4 undoes the multiplication by 4.
x=
4
3y−1
Answer:
1) 
2) 
3) 
4) 40
5) 
Step-by-step explanation:
1) Distribute the negative sign that is outside the parentheses and then you must add like terms, as following:

2) According to the Product property of exponents, when you multiply powers with the same base, you must add the exponents. Then:

3) Apply the Distributive property and the Product property of exponents. Then, you obtain:

4)
is a square of a sum, then, by definition you have:

Then:

The coefficient of the second term is the number in front of the variable <em>a.</em> Then, the answer is: 40
5) Apply the Distributive property and the Product property of exponents, then, oyou must add the like terms:

Answer:
Horizontal asymptote of the graph of the function f(x) = (8x^3+2)/(2x^3+x) is at y=4
Step-by-step explanation:
I attached the graph of the function.
Graphically, it can be seen that the horizontal asymptote of the graph of the function is at y=4. There is also a <em>vertical </em>asymptote at x=0
When denominator's degree (3) is the same as the nominator's degree (3) then the horizontal asymptote is at (numerator's leading coefficient (8) divided by denominator's lading coefficient (2)) 