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3 years ago

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The Bowling/Laser Tag Decision: A group of friends must decide how many games of bowling and laser tag to play. They decide to p

lay at least one game of bowling and at least one game of laser tag. Find the costs of different numbers of games to help Ernest decide how many games to play. Remember, they want to have money left over for snacks.

1 answer:

Elena L [17]3 years ago

3 0

How much do they spend though

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If tñ=2ñ+3, find S10

Allisa [31]

Answer:

$S_{10}=280$

Step-by-step explanation:

Given that,

$t_n=2n+3$ ...(1)

We need to find the value of $S_{10}$ .

Put n = 1 to find the first term.

$t_1=2(1)+3=5$

Put n = 2 to find the second term.

$t_2=2(2)+3=7$

Put n = 3 to find the third term.

$t_3=2(3)+3=9$

Put n = 10 to find the tenth term.

$t_{10}=2(10)+3=23$

It means we need to find the sum of 5,7,9,.....,23.

The formula for the sum of n terms is given by :

$S_=\dfrac{n}{2}(a+a_n)$

We have, n = 10, a = 5 and $a_n=23$

So,

$S=\dfrac{10}{2}(5+23)\\\\S_{10}=10\times 28\\\\=280$

So, the value of $S_{10}$ is equal to 280.

3 0

3 years ago

A ball is thrown vertically in the air with a velocity of 95 ft/s. The ball is at a height of 120 ft.

sattari [20]

Answer:

The ball is at a height of 120 feet after 1.8 and 4.1 seconds.

Step-by-step explanation:

The statement is incomplete. The complete statement is perhaps the following "A ball is thrown vertically in the air with a velocity of 95 ft/s. What time in seconds is the ball at a height of 120ft. Round to the nearest tenth of a second."

Since the ball is launched upwards, gravity decelerates it up to rest and moves downwards. The position of the ball can be determined as a function of time by using this expression:

$y = y_{o} + v_{o}\cdot t +\frac{1}{2}\cdot g \cdot t^{2}$

Where:

$y_{o}$ - Initial height of the ball, measured in feet.

$v_{o}$ - Initial speed of the ball, measured in feet per second.

$g$ - Gravitational constant, equal to $-32.174\,\frac{ft}{s^{2}}$ .

$t$ - Time, measured in seconds.

Given that $y_{o} = 0\,ft$ , $v_{o} = 95\,\frac{ft}{s}$ , $g = -32.174\,\frac{ft}{s^{2}}$ and $y = 120\,ft$ , the following second-order polynomial is found:

$120\,ft = 0\,ft + \left(95\,\frac{ft}{s} \right)\cdot t +\frac{1}{2}\cdot \left(-32.174\,\frac{ft}{s^{2}} \right) \cdot t^{2}$

$-16.087\cdot t^{2} + 95\cdot t -120 =0$

The roots of this polynomial are, respectively:

$t_{1} \approx 4.075\,s$ and $t_{2} \approx 1.831\,s$ .

Both roots solutions are physically reasonable, since $t_{1}$ represents the instant when the ball reaches a height of 120 ft before reaching maximum height, whereas $t_{2}$ represents the instant when the ball the same height after reaching maximum height.

In nutshell, the ball is at a height of 120 feet after 1.8 and 4.1 seconds.

8 0

3 years ago

Why was 56 and 36 points selected?

AleksAgata [21]

I don’t know , why don’t you tell me why they were selected

6 0

3 years ago

HELP PLLZZZZZZZZZZZZZZZZZZZ

Alex17521 [72]

18 1/4 pieces she will have now
:)

3 0

2 years ago

A line passes through the point (0, 5) and has a slope of - 1/2 . Which is the equation of the line in slope-intercept form?

sergey [27]

<span>The equation of the line that passes through the point (0,5) with a slope of 1/2</span>

<span>y=1/2x+5</span>

7 0

3 years ago