Answer:
t = 2.2 [days] and is there is a round trip, it will be double time t = 4.4 [days]
Explanation:
First, we need to arrange the problem to work in the same unit system (SI).
We need to convert the 1800 [miles] to meters, therefore:
![1800[miles] * \frac{1609.34[m]}{1[mile]} }=2896812[m] = 2896.8[km]](https://tex.z-dn.net/?f=1800%5Bmiles%5D%20%2A%20%5Cfrac%7B1609.34%5Bm%5D%7D%7B1%5Bmile%5D%7D%20%7D%3D2896812%5Bm%5D%20%3D%202896.8%5Bkm%5D)
Now using the following equation of kinematics, for the avarage velocity we have:
![v=\frac{x}{t} \\where \\v=velocity [m/s]\\t = time [s]\\x=distance traveled [m]\\](https://tex.z-dn.net/?f=v%3D%5Cfrac%7Bx%7D%7Bt%7D%20%5C%5Cwhere%20%5C%5Cv%3Dvelocity%20%5Bm%2Fs%5D%5C%5Ct%20%3D%20time%20%5Bs%5D%5C%5Cx%3Ddistance%20traveled%20%5Bm%5D%5C%5C)
therefore:
![t=\frac{x}{v} \\t=\frac{2896812}{15}\\ t=193120.8[s]](https://tex.z-dn.net/?f=t%3D%5Cfrac%7Bx%7D%7Bv%7D%20%5C%5Ct%3D%5Cfrac%7B2896812%7D%7B15%7D%5C%5C%20t%3D193120.8%5Bs%5D)
Now we can convert from seconds into days.
![193120.8[s]*\frac{1[hr]}{3600[s]}*\frac{1[day]}{24[hr]}\\ t = 2.2[days]](https://tex.z-dn.net/?f=193120.8%5Bs%5D%2A%5Cfrac%7B1%5Bhr%5D%7D%7B3600%5Bs%5D%7D%2A%5Cfrac%7B1%5Bday%5D%7D%7B24%5Bhr%5D%7D%5C%5C%20%20t%20%3D%202.2%5Bdays%5D)
Now if the truck has the need to come back, the team will spend double time.
t= 4.4 [days]
Answer:
. The SI unit of volume is the cubic meter (m3), which is a derived unit.
Liter (L) is a special name for the cubic decimeter (dm3).
Answer:
P₃ > P₁ > P₂
Explanation:
To rank pressure of the given situation
a) we know
Pressure at height h below
P = ρ g h
density of salt water, ρ = 1029 kg/m³
P₁ = 1029 x 10 x 0.2
P₁ = 2058 Pa
b) density of fresh water, ρ = 1000 kg/m³
P₂ = 1000 x 10 x 0.2
P₂ = 2000 Pa
c) density of mercury, ρ = 13593 kg/m³
P₃ = 13593 x 10 x 0.05
P₃ = 6796.5 Pa
Rank of Pressures from highest to lowest
P₃ > P₁ > P₂
If the two cars traveling opposite directions have the same mass, then yes, the momentum of a car traveling south will have the same momentum as a car traveling north at the same speed.
