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GuDViN [60]
3 years ago
7

What was the measurement of the wavelength and amplitude respectively?

Physics
1 answer:
SpyIntel [72]3 years ago
5 0
<h3>Answer</h3>

option C)

The wavelength has a length between 7.0 cm and 8.0 cm and the amplitude lies between 1.0 cm and 2.0 cm.

<h3>Explanation</h3><h2>1)</h2>

The amplitude of a wave is the height of a wave as measured from the highest point on the wave, peak, to the rest point or from  the lowest point on the wave, trough, to the rest point.

By looking at the image

rest point is at 5cm and crest is at 3.3 cm (y-axis)

so amplitude = 5 - 3.3

                      = 1.7 cm (approximately)

<h2>2)</h2>

Wavelength refers to the length of a wave from one peak to the next.

one crest is at 2cm and the other crest is at 10cm (x-axis)

so wavelength = 10 - 2

                          = 8 cm (approximately)

<h3 />
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A heat engine does 200 j of work per cycle while exhausting 600 j of heat to the cold reservoir. what is the engine's thermal ef
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The thermal efficiency of an engine is
\eta= \frac{W}{Q}
where
W is the work done by the engine
Q is the heat absorbed by the engine to do the work

In this problem, the work done by the engine is W=200 J, while the heat exhausted is Q=600 J, so the efficiency of the machine is
\eta= \frac{W}{Q}= \frac{200 J}{600 J}=0.33 = 33 \%
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Mamie clark was a psychologist who is known for her research on ?
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An internal resistance of 5 ohm and a battery of 15 ohm is connected to a resistance of 20 ohm calculate the electric current
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.6 A

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2 years ago
A rock is thrown off a 50.0 m high cliff. How fast must the rock leave the cliff top to land on level ground below, 90 m from th
blagie [28]

Answer:

The rock must leave the cliff at a velocity of 28.2 m/s

Explanation:

The position vector of the rock at a time t can be calculated using the following equation:

r = (x0 + v0x · t, y0 + 1/2 · g · t²)

Where:

r = position vector at time t.

x0 = initial horizontal position.

v0x = initial horizontal velocity.

t = time.

g = acceleration due to gravity (-9.81 m/s² considering the upward direction as positive).

Please, see the attached figure for a graphical description of the problem. Notice that the origin of the frame of reference is located at the edge of the cliff so that x0 and y0 = 0.

When the rock reaches the ground, the position vector will be (see r1 in the figure):

r1 = (90 m, -50 m)

Then, using the equation of the vector position written above:

90 m = x0 + v0x · t

-50 m = y0 + 1/2 · g · t²

Since x0 and y0 = 0:

90 m = v0x · t

-50 m = 1/2 · g · t²

Let´s use the equation of the y-component of the vector r1 to find the time it takes the rock to reach the ground and with that time we can calculate v0x:

-50 m = 1/2 · g · t²

-50 m = -1/2 · 9.81 m/s² · t²

-50 m / -1/2 · 9.81 m/s² = t²

t = 3.19 s

Now, using the equation of the x-component of r1:

90 m = v0x · t

90 m = v0x · 3.19 s

v0x = 90 m / 3.19 s

v0x = 28.2 m/s

8 0
3 years ago
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