All categories

2 years ago

What was the measurement of the wavelength and amplitude respectively?

Physics

1 answer:

SpyIntel [72]2 years ago

5 0

<h3>Answer</h3>

option C)

The wavelength has a length between 7.0 cm and 8.0 cm and the amplitude lies between 1.0 cm and 2.0 cm.

<h3>Explanation</h3><h2>1)</h2>

The amplitude of a wave is the height of a wave as measured from the highest point on the wave, peak, to the rest point or from the lowest point on the wave, trough, to the rest point.

By looking at the image

rest point is at 5cm and crest is at 3.3 cm (y-axis)

so amplitude = 5 - 3.3

= 1.7 cm (approximately)

Wavelength refers to the length of a wave from one peak to the next.

one crest is at 2cm and the other crest is at 10cm (x-axis)

so wavelength = 10 - 2

= 8 cm (approximately)

<h3 />

You might be interested in

Scientific work is currently underway to determine whether weak oscillating magnetic fields can affect human health. For example

nlexa [21]

Answer:

The maximum emf that can be generated around the perimeter of a cell in this field is $1.5732*10^{-11}V$

Explanation:

To solve this problem it is necessary to apply the concepts on maximum electromotive force.

For definition we know that

$\epsilon_{max} = NBA\omega$

Where,

N= Number of turns of the coil

B = Magnetic field

$\omega =$ Angular velocity

A = Cross-sectional Area

Angular velocity according kinematics equations is:

$\omega = 2\pi f$

$\omega = 2\pi*61.5$

$\omega =123\pi rad/s$

Replacing at the equation our values given we have that

$\epsilon_{max} = NBA\omega$

$\epsilon_{max} = NB(\pi (\frac{d}{2})^2)\omega$

$\epsilon_{max} = (1)(1*10^{-3})(\pi (\frac{7.2*10^{-6}}{2})^2)(123\pi)$

$\epsilon_{max} = 1.5732*10^{-11}V$

Therefore the maximum emf that can be generated around the perimeter of a cell in this field is $1.5732*10^{-11}V$

6 0

3 years ago

When objects are charged by _______, they do not need to touch each other.

Deffense [45]

C because conduction you don’t need to touch anything

6 0

3 years ago

Could you guys tell me whether the photo represents a balanced or unbalanced equation

NARA [144]

Answer:

that is preatty balenced m8

Explanation:

6 0

3 years ago

on a very muddy football field, a 120 kg linebacker tackles an 75 kg halfback. immediately before the collision, the linebacker

Aleksandr-060686 [28]

B4 the tackle:

<span>The linebacker's momentum = 115 x 8.5 = 977.5 kg m/s north </span>

<span>and the halfback's momentum = 89 x 6.7 = 596.3 kg m/s east </span>

<span>After the tackle they move together with a momentum equal to the vector sum of their separate momentums b4 the tackle </span>

<span>The vector triangle is right angled: </span>

<span>magnitude of final momentum = √(977.5² + 596.3²) = 1145.034 kg m/s </span>

<span>so (115 + 89)v(f) = 1145.034 ←←[b/c p = mv] </span>

<span>v(f) = 5.6 m/s (to 2 sig figs) </span>

<span>direction of v(f) is the same as the direction of the final momentum </span>

<span>so direction of v(f) = arctan (596.3 / 977.5) = N 31° E (to 2 sig figs) </span>

<span>so the velocity of the two players after the tackle is 5.6 m/s in the direction N 31° E </span>

<span>btw ... The direction can be given heaps of different ways ... N 31° E is probably the easiest way to express it when using the vector triangle to find it</span>

4 0

3 years ago

The speed of propagation of the action potential (an electrical signal) in a nerve cell depends (inversely) on the diameter of t

zysi [14]

Answer:

Explanation:

Speed of electrical nerve signal = 33 m /s

Distance travelled = 1.3 m

time taken = distance / speed

= 1.3 / 33

= .039 s

= 39 ms ( millisecond ) .

3 0

2 years ago