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Svetradugi [14.3K]
3 years ago
8

Un auto que acelera a razón de 2 m/S^2 ; Si para cierto tramo se observa que logra triplicar su rapidez en 6 s. ¿Cuál fue su rap

idez al final de estos 6 segundos?
Physics
1 answer:
katen-ka-za [31]3 years ago
8 0

Answer:

12m/s

Explanation:

Using the equation of  motion

v = u + at

Given that

u = 0m/s

a = 2m/s²

time t = 6s

Substitute the given values into the expression

v = 0 + 2(6)

v = 0+12

v = 12m/s

Hence the required velocity is 12m/s

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Which of the outer planets would you most likely visit? Why? What would you see on your visit?
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Brainliest answer?

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3 years ago
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Two bodies of masses 1000kg and 2000kg are separated 1km which is the gravitational force between them
denpristay [2]

Answer:

1.33×10⁻¹⁰ N

Explanation:

F = GMm / r²

where G is the gravitational constant,

M and m are the masses of the objects,

and r is the distance between them.

F = (6.67×10⁻¹¹ N/m²/kg²) (1000 kg) (2000 kg) / (1000 m)²

F = 1.33×10⁻¹⁰ N

3 0
4 years ago
What force is needed to propel a 421-kg car with an acceleration of 3.77 m/s2?
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7 0
3 years ago
KI + Cl2 ---&gt; KCl + I2<br> Balance the single replacement chemical reaction.
snow_lady [41]

Answer:

2KI   +  Cl₂   →   2KCl     +    I₂

Explanation:

The reaction equation is given as:

        KI   +  Cl₂   →    KCl     +    I₂

The problem at hand is to balance this chemical reaction. To solve this problem we use a mathematical approach;

        aKI   +  bCl₂   →    cKCl     +    dI₂

 Conserving K : a = c

                     I :  a  = 2d

                   Cl : 2b = c  

 Now let a = 1, c  = 1 , d  = \frac{1}{2}, b   = \frac{1}{2}, ;

   Multiply through by 2;

             a  = 2, b = 1 , c = 2, d  = 1

 

            2KI   +  Cl₂   →   2KCl     +    I₂

 

5 0
3 years ago
As a summer intern assigned to the Olympics Kayaking committee, you need to determine the speed of water flowing through a rapid
Nookie1986 [14]

Answer:

11.56521 m/s

Explanation:

A_1 = Area of first section = 14\times 2

A_2 = Area of second section = 5\times 0.92

V_1 = Velocity in first section = 1.9 m/s

V_2 = Velocity in second section

From the continuity equation we get

A_1V_1=A_2V_2\\\Rightarrow V_2=\dfrac{A_1V_1}{A_2}\\\Rightarrow V_2=\dfrac{14\times 2\times 1.9}{5\times 0.92}\\\Rightarrow V_2=11.56521\ m/s

The speed of the river through the section of rapids is 11.56521 m/s

5 0
3 years ago
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