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sweet [91]
3 years ago
7

A solid disk and a thin-walled hoop each have a diameter of 8 cm. Both are released from rest at the same time at the top of a r

amp that is 175 cm high and start rolling down the incline. What is the velocity of each at the bottom of the ramp? What percentage of the gravitational potential energy has been transformed into angular kinetic energy for each? Into what form of energy is the remaining percentage transformed?
Physics
1 answer:
maxonik [38]3 years ago
6 0

Answer:

Explanation:using

Mgh= 1/2mv²+1/2Iw²

So for disk

mgh= 1/2mv²+1/2(1/2mR²)v²/R²

gh = 0.75v²

V= 4.8m/s

Then the translational KE

= (1/2mv²)/mgh x 100

= 66.7%

So rotational energy= 100- 67.7%

=33.3%

For hoop

mgh= 1/2mv²+1/2(1/2mR²)v²/R²

V= 4.14m/s

Then the translational KE

= (1/2mv²)/mgh x 100

= 50%

Then the remaining 50% is translational energy

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Assume that when viewed from above, the current is flowing towards the top-right corner of the picture. Consider the wire near the top-right corner of this coil (as viewed above on this picture.) The current will be going into the picture into the magnetic field. By the right-hand rule, the current on the wire near that point should be pointing towards the bottom of this picture. (Point fingers on the right hand in the direction of the current I. Rotate the right hand such that when curling the fingers, they point in the direction of the magnetic field B. The direction of the right thumb should now point in the direction of the force on the wire F.)

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<h3><u>Answer;</u></h3>

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