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sweet [91]
3 years ago
7

A solid disk and a thin-walled hoop each have a diameter of 8 cm. Both are released from rest at the same time at the top of a r

amp that is 175 cm high and start rolling down the incline. What is the velocity of each at the bottom of the ramp? What percentage of the gravitational potential energy has been transformed into angular kinetic energy for each? Into what form of energy is the remaining percentage transformed?
Physics
1 answer:
maxonik [38]3 years ago
6 0

Answer:

Explanation:using

Mgh= 1/2mv²+1/2Iw²

So for disk

mgh= 1/2mv²+1/2(1/2mR²)v²/R²

gh = 0.75v²

V= 4.8m/s

Then the translational KE

= (1/2mv²)/mgh x 100

= 66.7%

So rotational energy= 100- 67.7%

=33.3%

For hoop

mgh= 1/2mv²+1/2(1/2mR²)v²/R²

V= 4.14m/s

Then the translational KE

= (1/2mv²)/mgh x 100

= 50%

Then the remaining 50% is translational energy

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What is the momentum of a 1200 kg car traveling with a speed of 27 m/s (60 mph)?
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Approximate the human form as an unclothed vertical cylinder of 0.3 m diameter and 1.75 m length with a surface temperature of 3
Zolol [24]

Answer:

q=1118.865W

Explanation:

From the question we are told that

Diameter of the cylinder D=0.3m

Length of the cylinder L=1.75m

Surface temperature of cylinder T_s=30 \textdegree C=303k

Speed of air V=10m/s

Temperature of air T=20 \textdegree C

Generally the equation for Reynolds number is mathematically given by

Re_D=\frac{VD}{v}

where

v=15.27*10^-^6

Re_D=\frac{10*0.3}{15.27*10^-^6}

Re_D=1.96*10^5

Generally the equation for Nusselt number is mathematically given by

N_u=0.6(Re_D)^{0.6}(Pr)^{0.37}

where

Prandtl number

Pr=0.71

N_u=0.6(Re_D)^{0.6}(Pr)^{0.37}

N_u=0.6(1.96*10^5)^{0.6}(0.71)^{0.37}

N_u=791.53

Generally the equation for convective heat transfer is mathematically given by

h=Nu \frac{k}{D}

where

k=25.7*10^{-3}

h=791.53*\frac{25.7*10^{-3}}{0.3}

h=67.81W/m^2K

Generally the equation for surface area of a cylinder is mathematically given by

A=\pi DL

A=\pi *0.3*1.75

A=1.65m^2

Generally the equation for convective heat transfer is mathematically given by

q=h4(T_s-T_{inty)}

q=(67.81)*1.65*(30-20)\\

q=1118.865W

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2 years ago
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