The probability that at least one of them will get scholarship is 0.93
<h3>How to determine the probability</h3>
The given parameters are:
P(Boy) = 0.75
P(Girl) = 0.72
The probability that at least one of them will get scholarship is calculated using
P = P(Boy only) or P(Girl only) or P(Both)
This is then calculated as:
P = 0.75 * (1 - 0.72) + 0.72 * (1 - 0.75) + 0.72 * 0.75
Evaluate the products
P = 0.21 + 0.18 + 0.54
Evaluate the sum
P = 0.93
Hence, the probability that at least one of them will get scholarship is 0.93
Read more about probability at:
brainly.com/question/25870256
#SPJ1
Is there an image or more info given??
I'm not sure I follow this as it's asked.
Answer:
hi dear I suppose the answer would be 6271$
The cube root of 2 is irrational. The proof that the square root of 2 is irrational may be used, with only slight modification. Assume the cube root of 2 is rational. Then, it may be written as a/b, where a and b are integers with no common factors. (This is possible for all nonzero rational numbers). Since a/b is the cube root of 2, its cube must equal 2. That is, (a/b)3 = 2 a3/b3 = 2 a3 = 2b3. The right side is even, so the left side must be even also, thatis, a3 is even. Since a3 is even, a is also even (because the cube of an odd number is always odd). Since a is even, there exists an integer c such that a = 2c. Now, (2c)3 = 2b3 8c3 = 2b3 4c3 = b3. The left side is now even, so the right side must be even too. The product of two odd numbers is always odd, so b3 cannot be odd; it must be even. Therefore b is even as well. Since a and b are both even, the fraction a/b is not in lowest terms, thus contradicting our initial assumption. Since the initial assumption cannot have been true, it must <span>be false, and the cube root of 2 is irrational.
</span>
Answer:
1 inch=5inch
the flag is 40 inches by 45 inches
Step-by-step explanation:
are the numbers at the bottom right answer choices?