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Ne4ueva [31]
3 years ago
7

What is sum of all odd numbers between 100 and 200

Mathematics
1 answer:
makkiz [27]3 years ago
5 0
Odd numbers are of the form:

2n-1

So first we need to know how many odd numbers there are between 100 and 200...

100<2n-1<200  add 1 to all terms

101<2n<201  divide all terms by 2

50.5<n<100.5, since n must be an integer

51≤n≤100 so there are 100-51+1=50 odd numbers

Notice that 2n-1 forms an arithmetic sequence from 101 to 199 in this instance.

The sum of any arithmetic sequence is the average of the first and last terms times the number of terms, mathematically:

s=(a+b)(n/2), where a and b are the first and last terms and n is the number of terms, we saw earlier that there are 50 terms and that a=101 and b=199 so:

s=(101+199)(50/2)

s=7500

So the sum of all odd numbers between 100 and 200 is 7500.
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Zebras migrate in a circle with a round trip of about 300 miles. They travel at 64 km/h. How many hours does it take zebra to do
Tresset [83]

Answer:

7.5 hours (7 hours and 30 minutes)

Step-by-step explanation:

ok Let's start with 64km/h.

1.6 km=1 mile,

64÷1.6=40miles

so 64km/h changes into 40miles/hour.

Zebras's round trip =300miles,

300/40=7.5

so answer is 7.5 hours.

8 0
3 years ago
What s the Lcm of 4 and 9
Likurg_2 [28]
The LCM for 4 and 9 is 36
8 0
3 years ago
Read 2 more answers
Krystal made 8 quarts of soup on Monday 5 quarts of soup on Tuesday and 5 quarts of soup on Wednesday. If she serves each guest
vazorg [7]

Answer:

To get the answer you need to add these together to find the total number of quarts she made.

8+5+5= 18 quarts of soup.

If everyone gets one cup, then 18 people are able to get soup.

The answer is 18 guests.

Step-by-step explanation:

Hope this helps!

5 0
3 years ago
Read 2 more answers
Divide these polynomials. (8x³ + 2x² - 7x + 2) ÷ (2x - 1)
Novay_Z [31]

Answer:

The answer is letter A.

(8x³ + 2x² - 7x + 2) ÷ (2x - 1)

8x³ + 2x² - 7x + 2 ÷ 2x - 1

(2x-1)(4x²+3x-2)÷2x-1

cancel 2x-1 so that the answer is 4x²+3x-2.

6 0
3 years ago
Find all the zeros of the equation<br> -3x^4 + 27x^2 + 1200 = 0
guajiro [1.7K]

Answer:

\displaystyle x=-5,\ x=5,\ x=4i,\ x=-4i

Step-by-step explanation:

Biquadratic Equation

It's a fourth-degree equation where the terms of degree 1 and 3 are missing. It can be solved for the variable squared as if it was a second-degree equation, and then take the square root of the results

Our equation is

\displaystyle -3x^4+27x^2+1200=0

If we call y=x^2, our equation becomes a second-degree equation

\displaystyle -3y^2+27y+1200=0

Dividing by -3

\displaystyle y^2-9y-400=0

Factoring

\displaystyle (y-25)(y+16)=0

It leads to these solutions

\displaystyle y=25\ ,\ y=-16

Taking back the change of variable, we have for the first solution

\displaystyle x^2=25\Rightarrow x=-5,x=5

Now for the second solution, we get imaginary (complex) values

\displaystyle x^2=-16\Rightarrow x=4i,\ x=-4i

Summarizing, the four solutions for x are

\displaystyle x=-5,\ x=5,\ x=4i,\ x=-4i

5 0
3 years ago
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