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pishuonlain [190]
3 years ago
9

Compare [3] and [ – 8|

Mathematics
1 answer:
mariarad [96]3 years ago
7 0

Answer:

3 > -8

Step-by-step explanation:

-8 -7 -6 -5 -4 -3 -2 -1 <u>0</u> 1 2 3 ....

-8< 3

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X^2 +6x+30 in vertex form
Elina [12.6K]

Answer:

Step-by-step explanation:

Factoring  x2-6x-30

The first term is,  x2  its coefficient is  1 .

The middle term is,  -6x  its coefficient is  -6 .

The last term, "the constant", is  -30

Step-1 : Multiply the coefficient of the first term by the constant   1 • -30 = -30

Step-2 : Find two factors of  -30  whose sum equals the coefficient of the middle term, which is   -6 .

     -30    +    1    =    -29

     -15    +    2    =    -13

     -10    +    3    =    -7

     -6    +    5    =    -1

     -5    +    6    =    1

     -3    +    10    =    7

     -2    +    15    =    13

     -1    +    30    =    29

7 0
3 years ago
Read 2 more answers
Algebra 1: Which of the following is the correct slope between (1, -1) and (2, 3)?
blsea [12.9K]
(2,3) I think. I'm not in Algebra 1, so yeah
7 0
3 years ago
Read 2 more answers
I could use some help on this​
jok3333 [9.3K]

Answer:

the answer is B

3 0
3 years ago
It costs you $10 to draw a sample size n=1 and measure the attribute of interest. you have a budget of $1,200
kicyunya [14]

<span>a.       </span>Do you have sufficient funds to estimate the population mean for the attribute of interest with a 95% confidence interval 4 units width? Assume that sd= 12

n= {[(Zalpha/2)^2]*[sd]^2}/ se^2

n= (1.96)^2*(12)^2/ (2)^2

n= 138.297 rounded up to 139

<span>There is not enough funds for this one since you’ll need 139 pieces and it costs 10 a piece, you’ll need 1390.</span>

b.      90% confidence interval

n= {[(Zalpha/2)^2]*[sd]^2}/ se^2

n= (1.645)^2*(12)^2/ (2)^2

n=98

There is enough funds since 98 pieces for 10 a piece is equal to 980.

6 0
3 years ago
Suppose that 5 J of work is needed to stretch a spring from its natural length of 30 cm to a length of 39 cm.
vesna_86 [32]

Answer

given,

work = 5 J

spring stretch form 30 cm to 39 cm

W = \dfrac{1}{2}kx^2

x = 0.39 - 0.30 = 0.09 m

5 = \dfrac{1}{2}k\times 0.09^2

k = \dfrac{5\times 2}{0.09^2}

k = 1234.568 N/m

a) work when spring is stretched from  32 cm to 34 cm

x₂= 0.34 -0.30 = 0.04 m

x₁ = 0.32 - 0.30 = 0.02

W = \dfrac{1}{2}k(x_2^2-x_1^2)^2

W = \dfrac{1}{2}\times 1234.568 \times (0.04^2-0.02^2)^2

W = 0.741 J

b) F = k x

  25 = 1234.568 × x

     x = 0.0205 m

     x = 2.05 cm

3 0
3 years ago
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