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RoseWind [281]
3 years ago
10

Jordan can swim 2 laps in minutes. Select the correct unit rates for the given situation.

Mathematics
1 answer:
viktelen [127]3 years ago
3 0
We don’t have a real question here so no one can answer that for you
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After analyzing a data set using the one-way ANOVA model, the same data are analyzed using the randomized block design ANOVA mod
Contact [7]

Answer: Always equal to

Step-by-step explanation:

A one way analysis of variance refers to the technique that is used in knowing if there's significant difference between two samples means.

Based on the options given, it should be noted that SS (Treatment) in the one-way ANOVA model is always equal to the SS (Treatment) in the randomized block design ANOVA model.

4 0
2 years ago
A certain geneticist is interested in the proportion of males and females in the population who have a minor blood disorder. In
lord [1]

Answer:

95% confidence interval for the difference between the proportions of males and females who have the blood disorder is [-0.064 , 0.014].

Step-by-step explanation:

We are given that a certain geneticist is interested in the proportion of males and females in the population who have a minor blood disorder.

A random sample of 1000 males, 250 are found to be afflicted, whereas 275 of 1000 females tested appear to have the disorder.

Firstly, the pivotal quantity for 95% confidence interval for the difference between population proportion is given by;

                        P.Q. = \frac{(\hat p_1-\hat p_2)-(p_1-p_2)}{\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+ \frac{\hat p_2(1-\hat p_2)}{n_2}} }  ~ N(0,1)

where, \hat p_1 = sample proportion of males having blood disorder= \frac{250}{1000} = 0.25

\hat p_2 = sample proportion of females having blood disorder = \frac{275}{1000} = 0.275

n_1 = sample of males = 1000

n_2 = sample of females = 1000

p_1 = population proportion of males having blood disorder

p_2 = population proportion of females having blood disorder

<em>Here for constructing 95% confidence interval we have used Two-sample z proportion statistics.</em>

<u>So, 95% confidence interval for the difference between the population proportions, </u><u>(</u>p_1-p_2<u>)</u><u> is ;</u>

P(-1.96 < N(0,1) < 1.96) = 0.95  {As the critical value of z at 2.5% level

                                             of significance are -1.96 & 1.96}  

P(-1.96 < \frac{(\hat p_1-\hat p_2)-(p_1-p_2)}{\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+ \frac{\hat p_2(1-\hat p_2)}{n_2}} } < 1.96) = 0.95

P( -1.96 \times {\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+ \frac{\hat p_2(1-\hat p_2)}{n_2}} } < {(\hat p_1-\hat p_2)-(p_1-p_2)} < 1.96 \times {\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+ \frac{\hat p_2(1-\hat p_2)}{n_2}} } ) = 0.95

P( (\hat p_1-\hat p_2)-1.96 \times {\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+ \frac{\hat p_2(1-\hat p_2)}{n_2}} } < (p_1-p_2) < (\hat p_1-\hat p_2)+1.96 \times {\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+ \frac{\hat p_2(1-\hat p_2)}{n_2}} } ) = 0.95

<u>95% confidence interval for</u> (p_1-p_2) =

[(\hat p_1-\hat p_2)-1.96 \times {\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+ \frac{\hat p_2(1-\hat p_2)}{n_2}} }, (\hat p_1-\hat p_2)+1.96 \times {\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+ \frac{\hat p_2(1-\hat p_2)}{n_2}} }]

= [ (0.25-0.275)-1.96 \times {\sqrt{\frac{0.25(1-0.25)}{1000}+ \frac{0.275(1-0.275)}{1000}} }, (0.25-0.275)+1.96 \times {\sqrt{\frac{0.25(1-0.25)}{1000}+ \frac{0.275(1-0.275)}{1000}} } ]

 = [-0.064 , 0.014]

Therefore, 95% confidence interval for the difference between the proportions of males and females who have the blood disorder is [-0.064 , 0.014].

8 0
3 years ago
WILL MARK BRAINLIEST!!! HELP ASAP!!!!
mafiozo [28]
1 5/6 × 2= 2.66 or 2 2/3.

HOPE THIS HELPS!!!!

6 0
3 years ago
Read 2 more answers
(EXTRA POINTS) Which of the following relations is a function?<br><br><br><br> file in question
Taya2010 [7]
I think it is a I am not sure though
6 0
3 years ago
A city planner designs a park that is a quadrilateral with vertices at J(−1, 1), K(1, 3), L(5, −1), and M(−3, −1). There is an e
Vadim26 [7]

use the eqn below to find the mid-pts

x-mid-pt = (x₁+x₂)/2

y-mid-pt = (y₁+y₂)/2

J(−1, 1), K(1, 3), L(5, −1), and M(−3, −1)

So

midpoint JK = (-1+1/2, 1+3/2) = (0,2)

midpoint KL = (1+5/2, 3+⁻1/2) = (3,1)

midpoint LM = (5+⁻3/2, ⁻1+⁻1/2) = (1,-1)

midpoint MJ = (⁻3+⁻1/2, -1+1/2) = (-2,0)


use the eqn to find distance:


d = √(x₂ - x₁)² + (y₂ - y₁)²


Distance between JK and LM = √(0⁻1)² + (2 - ⁻1)² = √1 + 9 = √10

Distance between JM and KL = √(3-⁻2)² + (1-0)² = √25 + 1 = √26

Scale is 10

Actual distance = 10*(√10 + √26) = 82.6 = 83 units


8 0
3 years ago
Read 2 more answers
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