Use the FOIL method to check your answer from part A.
1 answer:
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Answer:
Step-by-step explanation:
Given that tank has the shape of inverted circular cone
Height = 10 feet and radius = 4 feet
After water pumped out height = 5 ft
Hence volume of water pumped out =
Here we have r/h is constant always
Hence
Substitute to get volume of water pumped out =
Mass of water = density x volume =
Work done = force x displacement
= mass x accen x displacement
Here acceleration = gravity = 32.2 ft/sec^2
Displaement = height reduced = 5 ft
W=2912(32.2)(5)\pi =468832\pi foot -pound