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docker41 [41]
3 years ago
12

What is the surface area using integrals of these two lines. Y=10-x^2 and Y=x^2+2 from the bounds x=2 and x=-2.

Mathematics
1 answer:
Lelu [443]3 years ago
5 0

Check the picture below.

\bf \displaystyle\int\limits_{-2}^{2}~[\stackrel{\textit{above function}}{(10-x^2)}~~-~~\stackrel{\textit{below function}}{(x^2+2)}]dx\implies \int\limits_{-2}^{2}~(10-x^2-x^2-2)dx \\\\\\ \displaystyle\int\limits_{-2}^{2}~(8-2x^2)dx\implies \left. 8x\cfrac{}{} \right]_{-2}^{2}-\left. \cfrac{2x^3}{3} \right]_{-2}^{2} \\\\\\ ([16]-[-16])~~-~~\left( \left[ \cfrac{16}{3} \right]-\left[ -\cfrac{16}{3} \right]\right)\implies (32)~~-~~\left( \cfrac{32}{3} \right) \\\\\\ \cfrac{64}{3}\implies 21\frac{1}{3}

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irina1246 [14]

Answer:

\sqrt{85}

Step-by-step explanation:

Calculate the distance d using the distance formula

d = √ (x₂ - x₁ )² + (y₂ - y₁ )²

with (x₁, y₁ ) = (- 1, 4) and (x₂, y₂ ) = (6, - 2)

d = \sqrt{(6+1)^2+(-2-4)^2}

  = \sqrt{7^2+(-6)^2}

  = \sqrt{49+36}

  = \sqrt{85} ← exact distance

4 0
3 years ago
Type the correct answer in each box. Use numerals instead of words,
xeze [42]

Answer:

x = -6,3,15,-12; y = 11,5,-3,15

Step-by-step explanation:

Domain is the x value, so plugged in the x values into the equation and got the y values or range.

8 0
3 years ago
Graph y=8.5xy=8.5xy, equals, 8, point, 5, x.
Morgarella [4.7K]

Answer:

  • A, B, E

Step-by-step explanation:

<u>Given equation</u>

  • y = 8.5x

<u>Answer choices</u>

A. The equation represents a proportional relationship.

  • TRUE, it is in the form of y = kx

B. The unit rate of change of y with respect to x is 8.5

  • TRUE, y = mx + b, the slope m = 8.5 is the rate of change

C. The slope of the line is 2/17

  • False, the slope is 8.5

D. A change of 17 units in x results in a change of 2 units in y.

  • False, a change of x = 17 results in 17*8.5 = 144.5 units in y

E. A change of 4 units in x results in a change of 34 units in y.

  • TRUE, because 4*8.5 = 34
3 0
2 years ago
równanie zmiany prędkość autokaru poruszającego się po prostym odcinku szosy i rozpoczynającego hamowanie od szybkości 20m/s ma
Rasek [7]

Answer:

s = 22.5 m

Step-by-step explanation:

the equation for the speed change of a coach moving along a straight section of the road and starting braking at a speed of 20 m / s has the form v (t) = 25-5t. Using integral calculus, determine the coach's braking distance.

v (t) = 25 - 5 t

at t = 0 , v = 20 m/s

Let the distance is s.

s =\int v(t) dt\\\\s =\int (25 - 5t)dt\\\\s= 25 t - 2.5 t^2 \\

Let at t = t, the v = 20

So,

20 = 25 - 5 t

t = 1 s

So, s = 25 x 1 - 2.5 x 1 = 22.5 m

3 0
2 years ago
the formula for the area of a circle is A pi r^2 what is the radius of a circle with an area of 400 pi cm^2
Bogdan [553]

Answer: 20 cm

Step-by-step explanation: Isolate the variable by dividing each side by factors that don't contain a variable.

4 0
2 years ago
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