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docker41 [41]
3 years ago
12

What is the surface area using integrals of these two lines. Y=10-x^2 and Y=x^2+2 from the bounds x=2 and x=-2.

Mathematics
1 answer:
Lelu [443]3 years ago
5 0

Check the picture below.

\bf \displaystyle\int\limits_{-2}^{2}~[\stackrel{\textit{above function}}{(10-x^2)}~~-~~\stackrel{\textit{below function}}{(x^2+2)}]dx\implies \int\limits_{-2}^{2}~(10-x^2-x^2-2)dx \\\\\\ \displaystyle\int\limits_{-2}^{2}~(8-2x^2)dx\implies \left. 8x\cfrac{}{} \right]_{-2}^{2}-\left. \cfrac{2x^3}{3} \right]_{-2}^{2} \\\\\\ ([16]-[-16])~~-~~\left( \left[ \cfrac{16}{3} \right]-\left[ -\cfrac{16}{3} \right]\right)\implies (32)~~-~~\left( \cfrac{32}{3} \right) \\\\\\ \cfrac{64}{3}\implies 21\frac{1}{3}

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Step-by-step explanation:

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3 years ago
The radius of a semicircle is 3 feet. What is the semicircle's area?<br>Use 3.14 for Pi​
valentinak56 [21]

Answer:

14.13 ft²

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We were also asked to use π as 3.14.

We substitute into the formula to get:

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sergiy2304 [10]

Answer:

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.......

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Read 2 more answers
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