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pashok25 [27]
3 years ago
15

Sissy wants to enlarge a picture of a princess so that she can put it on the wall in her daughter’s room. What will be the area

of the enlarged picture on the wall? 24 in.2 108 in.2 224 in.2 486 in.2

Mathematics
2 answers:
gayaneshka [121]3 years ago
7 0

Answer:

486 in.2 is the answer!!

Step-by-step explanation:

alisha [4.7K]3 years ago
3 0

Answer:

= 486 in²

Step-by-step explanation:

Linear scale factor = Image distance/object distance

Therefore; Linear scale factor = OL'/OL

                                                 = 54/ 12

                                                 = 9/2

Area scale factor is equivalent to the square of linear scale factor

Thus;

Area scale factor = (9/2)²

                             = 81/4

Hence; 81/4 = Area of larger rectangle/Area of smaller rectangle

Area of the smaller rectangle = 4 ×6 = 24 in²

Therefore;

Area of enlarged or larger pic = 81/4× 24

                                                  <u>= 486 in²</u>

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Please give answer for this
andrew-mc [135]

Answer:

100 square cm

Step-by-step explanation:

Area of figure 1 = l *b = 10 *7 = 70 square cm

Area of figure 2  =  6* 5 = 30 square cm

Area of shape = 70 + 30 = 100 square cm

6 0
3 years ago
Find the value of each variables in the parallelogram
xenn [34]

Answer:

A = 28

B = 87

Step-by-step explanation:

18 + 10 = 28

103 -16 = 87

4 0
3 years ago
Solve for the balloon volume using the equation below
valentinak56 [21]

The volume of the balloon is 1441.64cm³.

<h3>How to calculate the volume?</h3>

The radius of the balloon is given as 7cm. Also, the equation to calculate the volume is given as c³/6π²

The circumference c will be:

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= 44

The volume will be:

= c³/6π²

= 44³/(6 × 3.14²)

= 85284/(59.1576)

= 1441.64

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3 0
2 years ago
A calculus exam has a mean of µ = 73 and a standard deviation of σ = 4. Trina's score on the exam was 79, giving her a z-score o
kirza4 [7]

Answer:

I get z = +1.8

x= 79

m= 73;s= 4;z= (x-m)/s= 1.5

hope it helps you

7 0
4 years ago
Adult tickets for the school play are $12.00 and children's tickets are $8.00. If a theatre holds 300 seats and the sold out per
Vaselesa [24]
Let x = number of adult tickets, and y = number of children tickets. One equation must deal with the number of tickets, and the other equation must deal with the revenue from the tickets.

Then x + y = 300 is the number of tickets
12x + 8y = 3280 is the revenue from the tickets.

Using the substitution method:

x + y = 300   ⇒   y = 300 - x   ⇒   Equation (3)

12x + 8y = 3280   ⇒   12x + 8(300-x) = 3280   ⇒   x = 220

y = 300 - x   ⇒   y = 300-220 ⇒ 80

Therefore 220 adult tickets and 80 children's tickets were sold.
6 0
4 years ago
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