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pashok25 [27]
3 years ago
15

Sissy wants to enlarge a picture of a princess so that she can put it on the wall in her daughter’s room. What will be the area

of the enlarged picture on the wall? 24 in.2 108 in.2 224 in.2 486 in.2

Mathematics
2 answers:
gayaneshka [121]3 years ago
7 0

Answer:

486 in.2 is the answer!!

Step-by-step explanation:

alisha [4.7K]3 years ago
3 0

Answer:

= 486 in²

Step-by-step explanation:

Linear scale factor = Image distance/object distance

Therefore; Linear scale factor = OL'/OL

                                                 = 54/ 12

                                                 = 9/2

Area scale factor is equivalent to the square of linear scale factor

Thus;

Area scale factor = (9/2)²

                             = 81/4

Hence; 81/4 = Area of larger rectangle/Area of smaller rectangle

Area of the smaller rectangle = 4 ×6 = 24 in²

Therefore;

Area of enlarged or larger pic = 81/4× 24

                                                  <u>= 486 in²</u>

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One zero of the polynomial function f(x) = x3 + x2 + 20x is x = 0. What are the zeros of the polynomial function?
daser333 [38]

Answer:

The correct option is C

Step-by-step explanation:

if f(x)= x3 + x2 - 20x

Replace f(x) by y

y = x3 + x2 - 20x

0 =x3 + x2 - 20x

x3 + x2 - 20x = 0

Take out x as a common:

x(x2+x-20)=0

Find factors of x2+x+20.

x(x^2+4x-5x-20) = 0

x{x(x+4)-5(x+4)}=0

x(x+4)(x-5)=0

Set x= 0

x=0 , x+4=0 , x-5 =0

x=0, x=0-4 , x=0+5

x=0, x= -4, x=5

x=(0,5,-4)

The correct option is C....

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What is the simplified form of the expression? (m^-1m^5/m^-2)^-3
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<h3>Answer: Choice E</h3>

======================================================

Explanation:

Think of 25 as 25/1 and 5 as 5/1

Choice E is really saying \frac{25}{1} \div \frac{5}{1} which becomes \frac{25}{1} \times \frac{1}{5}. Note the second fraction flips and we change to a multiplication sign.

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Or you could think of it like this:

25 \times \frac{1}{5} = \frac{25}{1} \times \frac{1}{5} = \frac{25*1}{1*5} = \frac{25}{5} = 25 \div 5

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