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3 years ago

bridget,jim and krutika hare some sweets in the ratio 2:3:3 bridge gets 22 sweets how many more sweets does jim get over bridget

Mathematics

1 answer:

xeze [42]3 years ago

5 0

Jim got 11 more sweets over Bridget.

Step-by-step explanation:

Given,

Bridget, Jim, Krutika got the sweets in the ratio of 2:3:3

Bridget got 22 sweets.

To find how many more sweets does Jim get over Bridget

Let,

Number of sweets they got 2x, 3x, 3x respectively

According to the problem,

2x = 22

or, x = 11

So, Jim got 33 sweets.

Jim got (33-22) = 11 more sweets over Bridget.

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Answer:

Distributive property says that:

(A + B)*C = A*C + B*C

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3 + 5*c*(2 + 6*c)

Here we can take the two terms inside the parentheses as A and B, and the term that multiplies them as C, then distributing we get:

3 + (5*c)*2 + (5*c)*(6*c)

Now remember that the multiplications are associative and commutative, then we can write this as:

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Answer:

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3 years ago

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3 years ago

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Answer:

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Step-by-step explanation:

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3 years ago

student randomly receive 1 of 4 versions(A, B, C, D) of a math test. What is the probability that at least 3 of the 5 student te

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Answer:

1.2%

Step-by-step explanation:

We are given that the students receive different versions of the math namely A, B, C and D.

So, the probability that a student receives version A = $\frac{1}{4}$ .

Thus, the probability that the student does not receive version A = $1-\frac{1}{4}$ = $\frac{3}{4}$ .

So, the possibilities that at-least 3 out of 5 students receive version A are,

1) 3 receives version A and 2 does not receive version A

2) 4 receives version A and 1 does not receive version A

3) All 5 students receive version A

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