Answer: 50.7 grams
Explanation:
To calculate the moles, we use the equation:

a) moles of 
![\text{Number of moles}=molarity\times {\text {Volume in L]}=0.417M\times 0.528L=0.220moles](https://tex.z-dn.net/?f=%5Ctext%7BNumber%20of%20moles%7D%3Dmolarity%5Ctimes%20%7B%5Ctext%20%7BVolume%20in%20L%5D%7D%3D0.417M%5Ctimes%200.528L%3D0.220moles)
The balanced chemical equation is:

is the limiting reagent as it limits the formation of product and
is in excess.
According to stoichiometry :
2 moles of
give = 1 mole of 
Thus 0.220 moles of
give=
of 
Mass of 
Thus 50.7 g of
will be formed.
Answer:
CH4 + 2 O2 - - - > CO2 + 2 H2O
Explanation:
hope this helps,
you can check by adding all the numbers on both sides
please mark it
Grams. liters is liquid. meters is length and atm is idk
Sulfur has 6 electrons, so we put 6 in the first spot.
Oxygen has 6 electrons too, but since there are 3, we would multiply 6 times 3 , which equals 18, then add that too.
The 2 is added because there is that negative 2 at the top of the formular, which indicates the presence of two extra valence electrons.
the equation would be
6 + 18 + 2 = 26