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alexdok [17]
3 years ago
12

Explain the resonance structures for the sulfite ion, SO32_.

Chemistry
1 answer:
daser333 [38]3 years ago
3 0
Two (-2) above the O3 means there are 2 extra electrons available for bonding. 

Polyatomic ions are groups of atoms joined together by covalent bonds, like molecules, except that they have a charge. The only difference between the process for drawing Lewis diagrams for molecules and for ions is in determining the number of available electrons. Count the valence as before then add an electron for each unit of negative charge or subtract one for each unit of positive charge. For example, the sulfite ion has the formula SO32-. The number of valence electrons is 6 + 3*6 + 2 = 26. 

<span>The atom with the highest electronegativity in the sulfite ion is the sulfur, so it belongs in the center of the diagram with oxygen atoms bonded to it. Fill in enough bonds to hold the ion together then add non-bonding electrons until all atoms obey the octet rule or you have used all that are available. 


I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!</span>
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Pre-zygotic, temporal separation

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3 years ago
What is the subscript of Carbon in Isovaleric acid C5H10O2
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2 years ago
A 34.53 ml sample of a solution of sulfuric acid, h2s04, reacts with 27.86 ml of 0.08964 m naoh solution. calculate the molarity
Gnoma [55]
The balanced equation between NaOH and H₂SO₄ is as follows
2NaOH + H₂SO₄ ---> Na₂SO₄ + 2H₂O
stoichiometry of NaOH to H₂SO₄ is 2:1
number of moles of NaOH moles reacted = molarity of NaOH x volume
number of NaOH moles = 0.08964 mol/L x 27.86 x 10⁻³ L = 2.497 x 10⁻³ mol
according to molar ratio of 2:1
2 mol of NaOH reacts with 1 mol of H₂SO₄
therefore 2.497 x 10⁻³ mol of NaOH reacts with - 1/2 x 2.497 x 10⁻³ mol of H₂SO₄
number of moles of H₂SO₄ reacted - 1.249 x 10⁻³ mol 
Number of H₂SO₄ moles in 34.53 mL - 1.249 x 10⁻³ mol 
number of H₂SO₄ moles in 1000 mL - 1.249 x 10⁻³ mol / 34.53 x 10⁻³ L = 0.03617 mol 
molarity of H₂SO₄ is 0.03617 M
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