Answer:
pH = 5.54
Explanation:
The pH of a buffer solution is given by the <em>Henderson-Hasselbach (H-H) equation</em>:
- pH = pKa + log
![\frac{[CH_3COO^-]}{[CH_3COOH]}](https://tex.z-dn.net/?f=%5Cfrac%7B%5BCH_3COO%5E-%5D%7D%7B%5BCH_3COOH%5D%7D)
For acetic acid, pKa = 4.75.
We <u>calculate the original number of moles for acetic acid and acetate</u>, using the <em>given concentrations and volume</em>:
- CH₃COO⁻ ⇒ 0.377 M * 0.250 L = 0.0942 mol CH₃COO⁻
- CH₃COOH ⇒ 0.345 M * 0.250 L = 0.0862 mol CH₃COOH
The number of CH₃COO⁻ moles will increase with the added moles of KOH while the number of CH₃COOH moles will decrease by the same amount.
Now we use the H-H equation to <u>calculate the new pH</u>, by using the <em>new concentrations</em>:
- pH = 4.75 + log
= 5.54
Answer:
Atoms are often more stable when bonded to other atoms
Explanation:
Like for example let's say ionic bonds..... Since one atom has to lose specific electrons to be stable and the other needs the electrons from the other atom to be stable.....
Answer:
What will determine the number of moles of hydronium in an aqueous solution of a strong monoprotic acid? The amount of acid that was added.
Explanation:
The ratio of reactants is chlorination of <u>2,3</u> dimethyl butane the possibility of obtaining do and the polychlorinated product is not seen.
When a mixture of methane and chlorine is exposed to ultraviolet light a substitution reaction occurs and the organic product is chloromethane. Because there are various hydrogen atoms that can be extracted in the first propagation step.
Abstraction of a hydrogen atom from the middle carbon of propane results in 2-chloropropane. In the presence of sunlight, methane reacts with chlorine to form chloromethane. The chlorination of methane is a free radical substitution reaction. Chlorine cannot turn into free radicals in the dark, so no reaction takes place. Therefore, the presence of sunlight is essential for the reaction to proceed.
Learn more about The reactants here:- brainly.com/question/6421464
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Answer:
Look at the image pls. The question is there
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