According to Ideal Gas Equation, Volume is related to Pressure and Temperature as follow,
P V = n R T
Or,
V = n R T / P
This relation shows that Volume is directly related to Temperature and Inversely related to pressure. So,
<span>A. Chilling a can of soda: As temperature is decreased so the volume will also decrease.
</span><span>B. Heating a hot-air balloon: As temperature is increased, so Volume will also increase.
</span><span>C. Squeezing a balloon: As pressure is applied, so volume will decrease.
</span><span>D. Pressurizing an air tank: Again pressure is applied so volume will decrease.</span>
Which of the following is described by the equation H2O(l) + heat → H2O(g)?
Answer: +H30
Answer:1. Or A
Explanation: I know this is right
(A) is the answer cause heating require to gain energy and freezing require to loss energy
hope you understand and good luck
Answer:
a) 88.48%
b) 0.05625 mol
Explanation:
2CH₃CH₂OH(l) → CH₃CH₂OCH₂CH₃(l) + H₂O(g) Reaction 1
CH₃CH₂OH(l) → CH₂═CH₂(g) + H₂O(g) Reaction 2
a) CH₃CH₂OH = 46.0684 g/mol
CH₃CH₂OCH₂CH₃ = 74.12 g/mol
1 mol CH₃CH₂OH ______ 46.0684 g
x ______ 50.0 g
x = 1.085 mol CH₃CH₂OH
1 mol CH₃CH₂OCH₂CH₃ ______ 74.12 g g
y ______ 35.9 g
y = 0.48 mol CH₃CH₂OCH₂CH₃
100% yield _____ 0.5425 mol CH₃CH₂OCH₂CH₃
w _____ 0.48 mol CH₃CH₂OCH₂CH₃
w = 88.48%
b) Only 0.96 mol of ethanol reacted to form diethyl ether. This means that 0.125 mol of ethanol did not react. 45% of 0.125 mol reacted to form ethylene. Therefore, 0.05625 mol of ethanol reacted by the side reaction (reaction 2). Since 1 mol of ethanol leads to 1 mol of ethylene, 0.05625 mol of ethanol produces 0.05625 mol of ethylene.