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Yuliya22 [10]
4 years ago
11

If a ribbon is 40 centimeters long and the other is 70 centimeters long and wants it to be the same length with no ribbon left o

ver how many pieces will she have in all
Mathematics
1 answer:
Stella [2.4K]4 years ago
5 0

Answer:

  11 pieces

Step-by-step explanation:

The greatest common divisor of 40 and 70 is 10. If each ribbon is cut into 10 cm pieces, there will be 4 pieces from the first ribbon, and 7 pieces from the second ribbon. The total number of pieces will be ...

  4 + 7 = 11 pieces

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Step-by-step explanation:

2(8)+4=20

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The sum of 8 and Jose's savings is 50.
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8 + x = 50, so Jose's saving or x = 42

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If two objects travel through space along two different curves, it’s often important to know whether they will collide. (Will a
galina1969 [7]

Answer:

<em>Both objects collide at t=3 in the point  <9,9,9></em>

Step-by-step explanation:

<em>Collision Of Moving Objects </em>

Two objects can describe different trajectories in the space. Those trajectories can intersect in one or more points but it doesn't mean they collide. Collision occurs if they are in the same position at the same time. If we know the positions as a function of time of each object, we could try so find if, for a given time, they are in the same position.

The positions of two object are given as

r1(t)=

r2(t)=

Let's find out if there is at least one value of t that makes both positions to be the same. We can try by equating one of the three coordinates and testing if the value of t make both have the same x,y,z coordinate. Let's try equating the x-components of both

t^2=4t-3

Rearranging

t^2-4t+3=0

Factoring

(t-1)(t-3)=0

We found two solutions

t=1,\ t=3

for t=1 the x-coordinates are

x1=t^2=1

x2=4t-3=1

For t=3

x1=t^2=9

x2=4t-3=9

Now we'll test both values in the y-coordinates

y1=7t-12

y2=t^2

For t=1

y1=-5

y2=1

Thus they don't collide at t=1. Let's try t=3

y1=7(3)-12=9

y2=3^2=9

Now let's try the z-coordinate for t=3

z1=t^2=9

z2=5t-6=9

Since the three coordinates match, we can say both objects collide at t=3 in the point  <9,9,9>

6 0
4 years ago
paul is diving and is 3.5 feet below sea level. he is descending at a rate of 0.5 feet per minute. if paul is now at 12 feet how
andrezito [222]

Answer:

He has been diving for 17 minutes

Step-by-step explanation:

* <em>Lets explain how to solve the problem</em>

- Paul is diving and is 3.5 feet below sea level

- He is descending at a rate of 0.5 feet per minute

- Paul is now at 12 feet

∵ His initial position is at 3.5 feet below the sea

∵ He is descending, that means he is moving down

∵ His final position is at 12

∴ <em>He is descending a distance = 12 - 3.5 = 8.5 feet</em>

∵ He is descending at a rate of 0.5 feet per minute

∵ He is descending 8.5 feet

∵ <em>Time = distance ÷ rate</em>

∴ <em>His time of descending = 8.5 ÷ 0.5 = 17 minutes</em>

* <em>He has been diving for 17 minutes</em>

5 0
3 years ago
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