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Makovka662 [10]
2 years ago
13

20 points plz help i dont really understand how to do this

Physics
1 answer:
Artist 52 [7]2 years ago
4 0

\huge{ \mathfrak{  \underline{ Answer} \:  \:  ✓ }}

1. Calculate the equivalent resistance in the circuit :

In the given diagram, the resistors are in series connection,

So equivalent resistance = sum of resistance of both resistors.

\large \boxed{R_{eq} =R_1 +R_2  }

  • R_{eq} =  480 + 360

  • R_{eq} = 840 \: ohms

Therefore, Equivalent resistance = 840 ohms.

2. Calculate the current through the battery :

\boxed{ \mathrm{current =  \dfrac{potential \:  \: difference}{resistance} }}

  • i =  \dfrac{120}{840}

  • i =  \dfrac{1}{7}

  • i = 0.142 \: Amperes

Hence, current through the battery = 0.142 A

3. How much current is passing through each resistor :

Since the resistors are joined in series connection, the current flowing through each resistor will be equal = 0.142 Amperes.

___________________________

\mathrm{ \#TeeNForeveR}

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4 0
2 years ago
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If neither of the bold words look familiar from your lesson feel free to ignore this answer

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2 years ago
a ball is projected upward at time t = 0.00 s from a point on a roof 70 m above the ground. The ball rises, then falls and strik
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Answer: 17.68 s

Explanation:

This problem is a good example of Vertical motion, where the main equation for this situation is:  

y=y_{o}+V_{o}t-\frac{1}{2}gt^{2} (1)  

Where:  

y=0 is the height of the ball when it hits the ground  

y_{o}=70 m is the initial height of the ball

V_{o}=82m/s is the initial velocity of the ball  

t is the time when the ball strikes the ground

g=9.8m/s^{2} is the acceleration due to gravity  

Having this clear, let's find t from (1):  

0=70m+(82m/s)t-\frac{1}{2}(9.8m/s^{2})t^{2} (2)  

Rewritting (2):

-\frac{1}{2}(9.8m/s^{2})t^{2}+(82m/s)t+70m=0 (3)  

This is a quadratic equation (also called equation of the second degree) of the form at^{2}+bt+c=0, which can be solved with the following formula:

t=\frac{-b \pm \sqrt{b^{2}-4ac}}{2a}  (4)

Where:

a=-\frac{1}{2}(9.8m/s^{2}

b=82m/s

c=70m

Substituting the known values:

t=\frac{-82 \pm \sqrt{82^{2}-4(-\frac{1}{2}(9.8)(70)}}{2a}  (5)

Solving (5) we find the positive result is:

t=17.68 s

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