For x^2-49
this is a diffarence of two perfect squares. I suggest that this is memorised.
a^2-b^2=(a-b)(a+b)
so x^2-7^2=(x-7)(x+7)
so to solve x^2+x-56 you want to find out what two numbers add to 1 and multiply to make -56
since -56 is negative we know that the two number are difarent signs so that eliminatess answers B and D.
if we try answer C -8+7=-1 so the answer is not C because we want +1 not -1
then we see that 8+(-7)=1 so the answer is A
Answer:
2x(x+6)(x-6)
Step-by-step explanation:
2x³-72
2x(x²-36)
2x(x+6)(x-6)
Answer:
T<-4.c
Step-by-step explanation:
If it’s “less than” then the stated number is the highest number that you can have
37. The absolute value symbol turns any negative number positive if it's within those brackets, so that's why the answer is positive. Hope this helped!
It can help you cause when you estimate your going back and putting the right number
