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iogann1982 [59]
2 years ago
7

Let's say that all of the tiny triangles are equivalent (which means the same size) and the base of one of them is 4 cm and the

height is 4 cm, what is the area of one of the tiny triangles?
Mathematics
1 answer:
KiRa [710]2 years ago
5 0

Answer:

8 cm^2. that is the answer

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A sculpture of a clothespin is 20 feet high. A normal clothespin of this shape is five inches high. Using this scale, how many f
kodGreya [7K]
This is the concept of scale factor. The linear scale factor is given by:
(height of sculpture)/(height of clothespin)
=20/(5/12)
=48
Given that a woman is 5ft 7 in, the sculpture of this woman would be:
height of sculpture=(scale factor)*(height of the woman)
height of the woman=5 ft 7 inches=5 7/12 ft=67/12 ft
hence the height of the sculpture will be:
67/12×48
=268 ft

Answer: 268 ft

7 0
3 years ago
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Can you guys help me out pls
kozerog [31]
Answer is for sure b
8 0
2 years ago
Find the smallest value of n such that the LCM of n and 15 is 45
krek1111 [17]

Answer:45


Step-by-step explanation:

9 and 15 both go into 45, and 45 is the LCM of those numbers.

6 0
3 years ago
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Which expression is equivalent to 2(3x+4)(x−1)(x−3)?
Vera_Pavlovna [14]

Answer:

A

Step-by-step explanation:

=(2(3x+4)(x−1))(x+−3)

=(2(3x+4)(x−1))(x)+(2(3x+4)(x−1))(−3)

=6x3+2x2−8x−18x2−6x+24

=6x3−16x2−14x+24

6 0
2 years ago
10-root18/root2 = a+broot2
Sauron [17]

Step-by-step explanation:

\frac{10 -  \sqrt{18} }{ \sqrt{2} } = a + b \sqrt{2}

\frac{10}{ \sqrt{2} }   +  \frac{ -  \sqrt{18} }{ \sqrt{2} }

5 \sqrt{2}   + (  \frac{ -  \sqrt{18} }{ \sqrt{2} } ) \times  \sqrt{2}

a = 5 \sqrt{2}

b =  \frac{ -  \sqrt{18} }{ \sqrt{2} }

8 0
2 years ago
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