Answer:
the two roots are x = 1 and x = 4
Step-by-step explanation:
Data provided in the question:
(x³ − 64) (x⁵ − 1) = 0.
Now,
for the above relation to be true the following condition must be followed:
Either (x³ − 64) = 0 ............(1)
or
(x⁵ − 1) = 0 ..........(2)
Therefore,
considering the first equation, we have
(x³ − 64) = 0
adding 64 both sides, we get
x³ − 64 + 64 = 0 + 64
or
x³ = 64
taking the cube root both the sides, we have
∛x³ = ∛64
or
x = ∛(4 × 4 × 4)
or
x = 4
similarly considering the equation (2) , we have
(x⁵ − 1) = 0
adding the number 1 both the sides, we get
x⁵ − 1 + 1 = 0 + 1
or
x⁵ = 1
taking the fifth root both the sides, we get
![\sqrt[5]{x^5}=\sqrt[5]{1}](https://tex.z-dn.net/?f=%5Csqrt%5B5%5D%7Bx%5E5%7D%3D%5Csqrt%5B5%5D%7B1%7D)
also,
1 can be written as 1⁵
therefore,
![\sqrt[5]{x^5}=\sqrt[5]{1^5}](https://tex.z-dn.net/?f=%5Csqrt%5B5%5D%7Bx%5E5%7D%3D%5Csqrt%5B5%5D%7B1%5E5%7D)
or
x = 1
Hence,
the two roots are x = 1 and x = 4
Answer:
hmmm l
Step-by-step explanation:
Answer:
Step 3, He should not switch the variables, you just don't do that.
(1) Answer : 
Step 1: 
Step 2: 
In completing the square method we take coefficient of x and divide by 2 and the square it . Then add it on both sides
The coefficient of x is -6. 
= (-3)^2 = 9
The coefficient of y is -4. 
= (-2)^2 = 4
Step : 
(2) 
To find center and radius we write the equation in the form of
using completing the square form
Where (h,k) is the center and 'r' is the radius
In completing the square method we take coefficient of x and divide by 2 and the square it . Then add it on both sides
Here h= -3 and k=3 and 
so r= 4
Center is (-3,3) and radius = 4
(c) Step 1: 
Step 2: 
Step 3: 
Step 4: 
We factor out each quadratic
(x^2 + 8x + 16) = (x+4)(x+4) = 
((y^2 - 6y + 9)) = (x-3)(x-3) = 
Step 5 :
