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harina [27]
4 years ago
7

Find the area of the rectangle 12ft by 9ft

Mathematics
1 answer:
Shtirlitz [24]4 years ago
6 0
The area is 12X9=108ft^2
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Which point do the graphs of f and g have in common?
pickupchik [31]

The point that the graphs of f and g have in common are (1,0)

<h3>How to get the points?</h3>

The given functions are:

f(x) = log₂x

and

g(x) = log₁₀x

We know that logarithm of 1 is always zero.

This means that irrespective of the base, the y-values of both functions will be equal to 0 at x=1

Therefore the point the graphs of f and g have in common is (1,0).

Learn more about graph on:

brainly.com/question/19040584

#SPJ1

6 0
2 years ago
Solve this problem please
sasho [114]
1.0465 is what I got.
7 0
3 years ago
Read 2 more answers
Data Set #1
Harman [31]

Answer:

The data table is attached below.

Step-by-step explanation:

The average of a set of data is the value that is a representative of the entire data set.

The formula to compute averages is:

\bar x=\frac{1}{n}\sum\limits^{n}_{i=1}{x_{i}}

Compute the average for drop 1 as follows:

\bar x_{1}=\frac{1}{3}\times[10+11+9]=10

Compute the average for drop 2 as follows:

\bar x_{2}=\frac{1}{3}\times[29+31+30]=30

Compute the average for drop 3 as follows:

\bar x_{3}=\frac{1}{3}\times[59+58+61]=59.33

Compute the average for drop 4 as follows:

\bar x_{4}=\frac{1}{3}\times[102+100+98]=100

Compute the average for drop 5 as follows:

\bar x_{5}=\frac{1}{3}\times[122+125+127]=124.67

The data table is attached below.

3 0
3 years ago
What are the restrictions for (x^2+10x+25)/(x^2-3x-28)<br><br> 0,14<br> -4,7<br> 0,7<br> 4,7
nirvana33 [79]
The answer is -4,7

The denominator can't equal zero. Factor the denominator:
x^2 - 3x - 28=
(X - 7)(x + 4); next set each set of parentheses equal to 0;
x - 7 = 0; so x=7 is one value
x + 4 = 0; so x=-4 is the other
Remember, x = 7 and x= -4 make the denominator zero, which is a "restriction" because you can't divide by zero.
5 0
3 years ago
A survey of 125 households was done to investigate whether households have laptops, tablets, or
riadik2000 [5.3K]

Answer:

3) 0.326

Step-by-step explanation:

Total Number of surveyed households =125

We want to determine the probability that a randomly selected household would have a laptop given that it does not  have a tablet.

Written in Probability notation: P(Laptop|No Tablet)

P(Laptop|No Tablet)=\dfrac{P(L\cap T')}{P(T')} \\=\dfrac{31/125}{95/125}\\=\dfrac{31}{95}\\\\=0.326

The correct option is C,

4 0
3 years ago
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