How do you know the speed of an electromagnetic wave in a vacuum?

1 answer:

7 0

The speed of electromagnetic waves in a vacuum is the same as the speed of light. It can be measured by finding the frequency and wavelength of two different waves, and then by that correlation, the speed of the waveform.
Hope this helps you (:

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Sanitation can be accomplished by all of the means except

Nonamiya [84]

Answer:

Air drying

Explanation:

Sanitation is the set of measures that aims to preserve or modify the conditions of the environment in order to prevent diseases and promote health, improve the quality of life of the population and the productivity of the individual and facilitate economic activity. Basic sanitation is a right guaranteed by the Constitution as the set of services, infrastructure and operational installations for water supply, sanitary sewage, urban cleaning, urban drainage, solid waste and rainwater management.

Sanitation can be carried out in several ways, except for dry air, as this would damage the quality of sanitation and the environment.

Sanitation is important in treated water, sewage collection and treatment services lead to an improvement in the quality of people's lives, especially in child health, with a reduction in child mortality, improvements in education, in the expansion of tourism, in the valuation of properties, in income of the worker, in the cleaning of rivers and preservation of water resources, etc.

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4 years ago

The accumulation of excess electric charge on an object is called.

andreev551 [17]

Answer: Static Electricty.

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3 years ago

Which of the following represents an element?

Digiron [165]

H2 is the correct answer

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3 years ago

wide tube that extends down from the bag of solution, which hangs from a pole so that the fluid level is 90.0 cm above the needl

Bingel [31]

Answer:

The average gauge pressure inside the vein is 110270.58 Pa

Explanation:

This question can be solved using the Bernoulli's Equation. First, in order to determine the outlet pressure of the needle, we need to find the total pressure exerted by the atmosphere and the fluid.

$P_f: fluid's\ pressure\\P_f= \rho g h=1025\frac{kg}{m^3} \times 9.8 \frac{m}{s^2} \times 0.9 m=9040.5 Pa \\P_T: total\ pressure\\P_T=P_{atm}+P_f\\P_T=101325 Pa + 9040.5 Pa=110275.5 Pa\\$

Then, we have to find the fluid's outlet velocity with the transversal area of the needle, as follows:

$S: transversal\ area \\S= \pi r^2=\pi (0.200 \times 10^{-3})^2=5.65 \times 10^{-7} m^2\\v=\frac{F}{S}=\frac{5.55 \times 10^{-8} \frac{m^3}{s}}{5.65 \times 10^{-7} m^2}=0.98\times 10^{-1} \frac{m}{s}$

As we have all the information, we can complete the Bernoulli's expression and solve to find the outlet pressure as follows:

$P_T-P_{out}=\frac{1}{2} \rho v^2\\P_{out}=P_T-\frac{1}{2} \rho v^2=110275.5 Pa-\frac{1}{2} 1025\frac{kg}{m^3} (0.98\times 10^{-1} \frac{m}{s})^2=110275.5 Pa-4.92 Pa =110270.58 Pa$