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jarptica [38.1K]
3 years ago
15

You connect a voltmeter to an unknown resistor in a circuit in order to measure the potential difference across that resistor. H

ow should you connect it to the resistor and what would the voltmeter's ideal internal resistance be? A. In series Fint B. In parallel; int- O C. In series; rint- 0 D. In parallel; rint →
Physics
2 answers:
scZoUnD [109]3 years ago
8 0

Answer:

option (a)

Explanation:

To make a galvanometer into voltmeter, we have to connect a high resistance in series combination.

The voltmeter is connected in parallel combination with teh resistor to find the voltage drop across it.

An ideal voltmeter has very high resistance that means it has a resistance as infinity.

Masteriza [31]3 years ago
7 0

Answer:

A. In series Fint

Explanation:

If you connect it to the resistor, the voltmeter's ideal internal resistance be  In series Fint.

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Please help. 8th grade science
Aneli [31]

Answer:

false

Explanation:

It doesn't the copper wire wouldn't even be pulled by the magnet at all and the electricity would stay inside of the the force of the copper wire

3 0
2 years ago
A charged object traveling 7 m in a uniform electric field of 5 N/C experiences a 4 J increase in Kinetic Energy.
Travka [436]

To solve this problem it is necessary to apply the principles of conservation of Energy in order to obtain the final work done.

The electric field in terms of the Force can be expressed as

E = \frac{F}{q} \rightarrow F=Eq

Where,

F = Force

E= Electric Field

q = Charge

Puesto que el trabajo realizado es equivalente al cambio en la energía cinetica entonces tenemos que

KE = W

KE = F*d

In the First Case,

4 = (qE)d\\q = \frac{4}{Ed}\\q = \frac{4}{5*7}\\q = 0.1142C

In Second Case,

KE = q E'd

KE = (0.1142)(40)(7)

KE = 31.976J

The total energy change would be subject to,

\Delta KE = 31.976-4

\Delta KE = 27.976J

Therefore the Kinetic Energy change of the charged object is 27.976J

3 0
2 years ago
What is glucose made of
tigry1 [53]

Glucose is a simple sugar.

Its chemical formula is  C₆ H₁₂ O₆ .

That tells you that every glucose molecule is made of 6 atoms of carbon,
12 atoms of hydrogen, and 6 atoms of oxygen.


3 0
3 years ago
A 2.50-m segment of wire carries 1000 A current and feels a 4.00-N repulsive force from a parallel wire 5.00 cm away. What is th
Stolb23 [73]

Answer:

The current is  I_b  =  400 \ A

Explanation:

From the question we are told that

    The  length of the segment is  l  =  2.50  \  m

     The current is  I_a  =  1000 \ A

     The force felt is  F  =  4.0 \  N

        The distance of the second wire is  d =  5.0 \ cm  = 0.05 \  m

Generally the current on the second wire is mathematically represented as

        I_b  =  \frac{2 \pi * r * F }{ l *  \mu_o  *  I_a }

Here  \mu_o is the permeability of free space with value  \mu_o =  4 \pi * 10^{-7} \ N/A^2

=>      I_b  =  \frac{2 * 3.142  *  0.05 *  4 }{ 2.50  *  4\pi *10^{-7}  * 1000 }

=>      I_b  =  400 \ A

4 0
2 years ago
outward from a wall just above floor level. A 1.5 kg box sliding across a frictionless floor hits the end of the spring and comp
sweet [91]

Answer:

v = 0.489 m/s

Explanation:

It is given that,

Mass of a box, m = 1.5 kg

The compression in the spring, x = 6.5 cm = 0.065 m

Let the spring constant of the spring is 85 N/m

We need to find the velocity of the box (v) when it hit the spring. It is based on the conservation of energy. The kinetic energy of spring before collision is equal to the spring energy after compression i.e.

\dfrac{1}{2}mv^2=\dfrac{1}{2}kx^2

v=\sqrt{\dfrac{kx^2}{m}} \\\\v=\sqrt{\dfrac{85\times (0.065)^2}{1.5}} \\\\v=0.489\ m/s

So, the speed of the box is 0.489 m/s.

3 0
3 years ago
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