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solong [7]
3 years ago
9

Determine the ratio of the resistivity of pure water to silver?

Physics
1 answer:
shutvik [7]3 years ago
3 0
Silver is a very good conductor, this means its resistivity is very low (from table, we can check the precise value, which is \rho_s = 1.6 \cdot 10^{-8} \Omega m).

Pure water, instead, is a very bad conductor, this means its resistivity is very high, of order of k \Omega \cdot m (10^3 \Omega m ). Even without knowing the precise value of the pure water resistivity, we can estimate the ratio between the pure water resistivity and the silver resistivity by comparing the two orders of magnitude:
r= \frac{10^3 \Omega m}{10^{-8} \Omega m}  \sim 10^{11}

Therefore, we can say that the correct answer is
3 \cdot 10^{11} : 1
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Answer:

(i) 12 seconds

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(iii) 132 meters from the initial position

(iv) No

Explanation:

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v=u+at

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In this case, v=0, u=36 m/s, a=-3 m/s^2

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(ii) To compute the distance traveled, s, till the express train stops, using

v^2=u^2+2as

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\Rightarrow s=\frac{36\times36}{6}

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(iv) Let 0 be the reference position which is the initial position of the express train.

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After 12 seconds:

The position of the express train is at 216 m [using part (ii)]

and the position of the local train is at 100+132=232m  [using part (iii)].

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