All categories

3 years ago

Find the difference quotient and simplify your answer. f(x) = x^3 + 3x, (f(x + h) - f(x))/h

Mathematics

1 answer:

kiruha [24]3 years ago

5 0

F x (x + h) - fx/h
fx +fh - fx /h
fh/h
f
So f is the answer

You might be interested in

Lin solved the equation 8 (x - 3) +7= 2x (4 - 17) incorrectly.

svet-max [94.6K]

Answer:

Her final answer should have been x = 1/2.

Step-by-step explanation:

Her 2 errors were that she didn't distribute the 2x to both 4 and -17 and that she made the 13 positive instead of negative when she added 4 and -17 together.

Correct solution:

8(x-3)+7=2x(4-17)

8x-24+7=8x-34x

-17=-34x

The negatives on both sides cancel each other out

x = 1/2

5 0

3 years ago

Read 2 more answers

if in a parallelogram diagonals bisect each other at right angle and are equal then it is a ___________

andrew11 [14]

Answer:

A parallelogram with one right angle is a rectangle. A quadrilateral whose diagonals are equal and bisect each other is a rectangle.

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

Hi, can someone help me pretty please?

Tju [1.3M]

It’s 174 square feet

3 0

2 years ago

Read 2 more answers

Day, everything at a store is on sale. The store offers a 20% discount.

Nutka1998 [239]

Answer:

$14.40

Step-by-step explanation:

$18-20%=$14.40

4 0

3 years ago

Joe is building a post for his mailbox. To find the correct dimensions, he needs to expand this expression: (x-3) (x-9) (x-4) Se

kolbaska11 [484]

Answer:

$(x-3)(x-9)(x-4)=x^3-16x^2+75x-108$

Step-by-step explanation:

Given:

The expression to expand is given as:

$(x-3)(x-9)(x-4)$

Let us expand the first two binomials of the given expression using FOIL method.

The FOIL method states that:

$(a + b)(c + d) = ac + ad + bc + bd$

$(x-3)(x-9)=(x\times x)+(x\times -9)+(-3\times x)+(-3\times -9)\\\\(x-3)(x-9)=x^2-9x-3x+27=x^2-12x+27$

Now, let us multiply the result with the remaining binomial. Multiplying each term of the trinomial with each term of the binomial, we get:

$(x^2-12x+27)(x-4)\\\\= (x^2\times x)+ (x^2\times -4)+(-12x\times x)+(-12x\times -4)+(27\times x)+(27\times -4)\\\\=x^3-4x^2-12x^2+48x+27x-108\\\\=x^3-16x^2+75x-108...........(\because-12x^2-4x^2=-16x^2,48x+27x=75x)$

Therefore, the equivalent expression after expanding is given as:

$(x-3)(x-9)(x-4)=x^3-16x^2+75x-108$

3 0

3 years ago