11.39g PbCl2(s) 200.0 ML Solve for m

What fraction can be used in conversion of 32 m3 to mm3

zimovet [89]

The calculation is (Measurement in m³ x 1000³)

Therefore

Measurement in m³ x 1 000 000

Its not a fraction as there are 1000mm in a m, so to convert from m to mm you must multiply

5 0

3 years ago

Read 2 more answers

) PABA refers to para-aminobenzoic acid which is used in some sunscreen formulations. If a 0.055 M solution of PABA has a pH of

AleksandrR [38]

Answer: $K_a$ of PABA is 0.000022

Explanation:

$NH_2C_6H_5COOH\rightarrow H^++NH_2C_6H_5COO^-$

cM 0 0

$c-c\alpha$ $c\alpha$ $c\alpha$

So dissociation constant will be:

$K_a=\frac{(c\alpha)^{2}}{c-c\alpha}$

Give c= 0.055 M and $\alpha$ = ?

$K_a=?$

$pH=-log[H^+]$

$2.96=-log[H^+]$

$[H^+]=1.09\times 10^{-3}$

$[H^+]=c\times \alpha$

$1.09\times 10^{-3}=0.055\times \alpha$

$\alpha=0.02$

Putting in the values we get:

$K_a=\frac{(0.055\times 0.02)^2}{(0.055-0.055\times 0.02)}$

$K_a=0.000022$

Thus $K_a$ of PABA is 0.000022

5 0

2 years ago

Fatty acids spread spontaneously on water to form a monomolecular film. A solution containing 0.10 mm^3 of a fatty acid is dropp

lara31 [8.8K]

Divide the volume by the area. Using scientific makes things a bit cleaner.

$0.10\,\mathrm{mm}^3 = 10^{-1}\,\mathrm{mm}^3$

$400.\,\mathrm{cm}^2 = 4\times10^2\,\mathrm{cm}^2$

Then

$\dfrac{10^{-1} \,\mathrm{mm}^3}{4\times10^2\,\mathrm{cm}^2} \cdot \dfrac{\left(\frac{1\,\rm m}{10^3\,\rm mm}\right)^3}{\left(\frac{1\,\rm m}{10^2\,\rm cm}\right)^2} = \dfrac{10^{-1}\times10^{-9} \,\mathrm m^3}{4\times10^2\times10^{-4}\,\mathrm m^2} = \dfrac{10^{-10}}{4\times10^{-2}}\,\mathrm m \\\\ ~~~~~~~~= 0.25\times10^{-8}\,\mathrm m$