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3 years ago

Determine the volume at STP of 36.8 g of nitrogen dioxide (NO2)

Chemistry

1 answer:

alexandr1967 [171]3 years ago

6 0

17.92L

Explanation:

Given parameters:

Mass of NO₂ = 36.8g

Condition = STP

Unknown:

Volume of gas = ?

Solution:

The volume of gas can be determined at STP if the number of moles of that gas is known.

Volume of NO₂ at STP = number of moles x 22.4

Number of moles = $\frac{mass}{molar mass}$

Molar mass of NO₂ = 14 + 2(16) = 46g/mol

Number of moles = $\frac{36.8}{46}$ = 0.8mole

Now;

Volume of NO₂ = 0.8 x 22.4 = 17.92L

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Explanation:

given Data:

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Where;

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ΔG° =[1mol*ΔG°f (PbBr₂)] - [1 mol *ΔG°f (Pb²⁺) +2mol *ΔG°f (2Br⁻)]

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ΔG = ΔG° + RTlnQ

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