23.4375 or 24.0 is the bacteria count after 6 hours.
2(5*4)+2(4*3)+2(3*5)=94 sq.m (Orginial SA)
2(4*5)+2(5*6)+2(6*4)=148 sq.m (Total SA)
148-94=54 (New SA)
Answer:
(7,3)
Step-by-step explanation:
Given,7 units away from x axis and 3 units away from y axis,
Coordinates are written in (x,y) form
(x,y)=(7,3)(Given)
Answer:
The distance cover by him walking back is 11.25 miles
Step-by-step explanation:
Given as :
Time for Janelle to spend on training = 5 hours
The running speed of Janelle = 9 mph
The walking back with 3 mph
Let The distance for running and walking is same i.e D miles
SO, Time = 
∴ 5 =
+ 
Or, 5 × 9 = D + 3 D
Or, 45 = 4 D
∴ D =
= 11.25 miles
Hence The distance cover by him walking back is 11.25 miles Answer
<span>Call x the distance traveled
V = x / t = 89.5 = x / t => x = 89.5t
Rest time in hours = 22min * 1 h / 60 min = 11/30 h
Total time spent on the trip = t + 11/30
=> Average speed = 77.8 = x / (t + 11/30)=> x = 77.8 (t + 11/30)
=> 89.5t = 77.8 (t + 11/30)
=> 89.5t = 77.8t + 77.8 * 11/30
=> 89.5 – 77.8t = 28.527
=> 11.7 t = 28.527
=> t = 28.527 / 11.7
=> t = 2.44 h => t + 11/30 = 2.81 h
=> x = 89.5t = 89.5 * 2.44 = 218.3 km
Answers: a) 2.81 h; b) 218.3 h
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